Question

A metal rod of length 2 m is rotated with a frequency 60 rev/s about an axis passing through its centre and perpendicular to its length. A uniform magnetic field of 2T perpendicular to its plane of rotation is switched-on in the region. Calculate the e.m.f. induced between the centre and the end of the rod.

Answer 1

`ε = 1/2 BωL^2`

Given Values

B = 2T

Frequency f = 60 rev/s

Length from centre to end L = 1m

ω = 2πf = 2π × 60 = 120 πrad/s

`ε=1/2xx2xx120pi xx (1)^2 = 120piV`

ε ≈ 120 × 3.1416

= 376.99 V

ε = 377 V