Advertisements
Advertisements
प्रश्न
A metal rod of length 2 m is rotated with a frequency 60 rev/s about an axis passing through its centre and perpendicular to its length. A uniform magnetic field of 2T perpendicular to its plane of rotation is switched-on in the region. Calculate the e.m.f. induced between the centre and the end of the rod.
संख्यात्मक
Advertisements
उत्तर
`ε = 1/2 BωL^2`
Given Values
B = 2T
Frequency f = 60 rev/s
Length from centre to end L = 1m
ω = 2πf = 2π × 60 = 120 πrad/s
`ε=1/2xx2xx120pi xx (1)^2 = 120piV`
ε ≈ 120 × 3.1416
= 376.99 V
ε = 377 V
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
