Advertisements
Advertisements
Question
A man’s age is three times that of his son, and in twelve years he will be twice as old as his son would be. What are their present ages.
Advertisements
Solution
Let present age of the son = x years
present age of the man = 3x years
In 12 years :
Son’s age will be = (x + 12) years
The man’s age will be = (3x + 12) years
According to the statement :
3x + 12 = 2(x + 12)
⇒ 3x + 12 = 2x + 24
⇒ 3x – 2x = 24 – 12
⇒ x = 12
3x = 3 x 12 = 36
Hence, present age of the man = 36 years
Present age of the son = 12 years.
APPEARS IN
RELATED QUESTIONS
Solve the following equation:
`(3"x")/("x" + 6) - "x"/("x" + 5) = 2`
If Megha’s age is increased by three times her age, the result is 60 years. Find her age
Separate 178 into two parts so that the first part is 8 less than twice the second part.
Six more than one-fourth of a number is two-fifth of the number. Find the number.
The difference of two numbers is 3 and the difference of their squares is 69. Find the numbers.
Three consecutive whole numbers are such that if they be divided by 5, 3 and 4 respectively; the sum of the quotients is 40. Find the numbers.
Solve:
`1/10 - 7/x = 35`
Solve: `(3"x" - 2)/3 + (2"x" + 3)/2 = "x" + 7/6`
Solve the following inequation
6x – 7 ≥ 35, where x is an integer
Solve the following inequalities
6(x + 6) ≥ 5(x – 3), x is a whole number
