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Question
A man’s age is three times that of his son, and in twelve years he will be twice as old as his son would be. What are their present ages.
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Solution
Let present age of the son = x years
present age of the man = 3x years
In 12 years :
Son’s age will be = (x + 12) years
The man’s age will be = (3x + 12) years
According to the statement :
3x + 12 = 2(x + 12)
⇒ 3x + 12 = 2x + 24
⇒ 3x – 2x = 24 – 12
⇒ x = 12
3x = 3 x 12 = 36
Hence, present age of the man = 36 years
Present age of the son = 12 years.
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