Advertisements
Advertisements
प्रश्न
A man’s age is three times that of his son, and in twelve years he will be twice as old as his son would be. What are their present ages.
Advertisements
उत्तर
Let present age of the son = x years
present age of the man = 3x years
In 12 years :
Son’s age will be = (x + 12) years
The man’s age will be = (3x + 12) years
According to the statement :
3x + 12 = 2(x + 12)
⇒ 3x + 12 = 2x + 24
⇒ 3x – 2x = 24 – 12
⇒ x = 12
3x = 3 x 12 = 36
Hence, present age of the man = 36 years
Present age of the son = 12 years.
APPEARS IN
संबंधित प्रश्न
Solve the following equation:
20 = 6 + 2x
Solve: `(4-3"x")/5 + (7 - "x")/3 + 4 1/3 = 0` Hence, find the value of 'p', if 3p - 2x + 1 = 0
28 is 12 less than 4 times a number. Find the number.
Six more than one-fourth of a number is two-fifth of the number. Find the number.
A man is 42 years old and his son is 12 years old. In how many years will the age of the son be half the age of the man at that time?
The present age of a man is twice that of his son. Eight years hence, their ages will be in the ratio 7 : 4. Find their present ages
Solve: `1/3"x" - 6 = 5/2`
Solve:
13(x − 4) - 3(x − 9) − 5(x + 4) = 0
The ages of A and B are in the ratio 7 : 5. Ten years hence, the ratio of their ages will be 9 : 7. Find their present ages.
The cost of one pen is ₹ 8 and it is available in a sealed pack of 10 pens. If Swetha has only ₹ 500, how many packs of pens can she buy at the maximum?
