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Karnataka Board PUCPUC Science Class 11

A man, of mass m, standing at the bottom of the staircase, of height L climbs it and stands at its top. Work done by all forces on man is equal to the rise in potential energy mgL. - Physics

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Question

A man, of mass m, standing at the bottom of the staircase, of height L climbs it and stands at its top.

  1. Work done by all forces on man is equal to the rise in potential energy mgL.
  2. Work done by all forces on man is zero.
  3. Work done by the gravitational force on man is mgL.
  4. The reaction force from a step does not do work because the point of application of the force does not move while the force exists.
Short/Brief Note
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Solution

b and d

Explanation:

When a man of mass m climbs up the staircase of height L, work done by the gravitational force on the man = – mgL

Work done by internal muscular forces = – Work done against gravitational force = mgL

Work done by all the forces = mgL – mgL = 0

As the point of application of the contact forces does not move, hence work done by reaction forces will also be zero.

And work done by friction will also be zero as there a no dissipation or rubbing involved.

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Chapter 6: Work, Energy and Power - Exercises [Page 44]

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NCERT Exemplar Physics [English] Class 11
Chapter 6 Work, Energy and Power
Exercises | Q 6.19 | Page 44

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