हिंदी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान कक्षा ११

A man, of mass m, standing at the bottom of the staircase, of height L climbs it and stands at its top. Work done by all forces on man is equal to the rise in potential energy mgL.

Advertisements
Advertisements

प्रश्न

A man, of mass m, standing at the bottom of the staircase, of height L climbs it and stands at its top.

  1. Work done by all forces on man is equal to the rise in potential energy mgL.
  2. Work done by all forces on man is zero.
  3. Work done by the gravitational force on man is mgL.
  4. The reaction force from a step does not do work because the point of application of the force does not move while the force exists.
टिप्पणी लिखिए
Advertisements

उत्तर

b and d

Explanation:

When a man of mass m climbs up the staircase of height L, work done by the gravitational force on the man = – mgL

Work done by internal muscular forces = – Work done against gravitational force = mgL

Work done by all the forces = mgL – mgL = 0

As the point of application of the contact forces does not move, hence work done by reaction forces will also be zero.

And work done by friction will also be zero as there a no dissipation or rubbing involved.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Work, Energy and Power - Exercises [पृष्ठ ४४]

APPEARS IN

एनसीईआरटी एक्झांप्लर Physics Exemplar [English] Class 11
अध्याय 6 Work, Energy and Power
Exercises | Q 6.19 | पृष्ठ ४४

संबंधित प्रश्न

In figure (i) the man walks 2 m carrying a mass of 15 kg on his hands. In Figure (ii), he walks the same distance pulling the rope behind him. The rope goes over a pulley, and a mass of 15 kg hangs at its other end. In which case is the work done greater?


Is work-energy theorem valid in non-inertial frames?

 

A ball is given a speed v on a rough horizontal surface. The ball travels through a distance l on the surface and stops. What is the work done by the kinetic friction? 


The US athlete Florence Griffith-Joyner won the 100 m sprint gold medal at Seoul Olympics in 1988, setting a new Olympic record of 10⋅54 s. Assume that she achieved her maximum speed in a very short time and then ran the race with that speed till she crossed the line. Take her mass to be 50 kg. Calculate the kinetic energy of Griffith-Joyner at her full speed. 


The US athlete Florence Griffith-Joyner won the 100 m sprint gold medal at Seoul Olympics in 1988, setting a new Olympic record of 10⋅54 s. Assume that she achieved her maximum speed in a very short time and then ran the race with that speed till she crossed the line. Take her mass to be 50 kg. Assuming that the track, wind etc. offered an average resistance of one-tenth of her weight, calculate the work done by the resistance during the run. 


The US athlete Florence Griffith-Joyner won the 100 m sprint gold medal at Seoul Olympics in 1988, setting a new Olympic record of 10⋅54 s. Assume that she achieved her maximum speed in a very short time and then ran the race with that speed till she crossed the line. Take her mass to be 50 kg.  What power Griffith-Joyner had to exert to maintain uniform speed?


An unruly demonstrator lifts a stone of mass 200 g from the ground and throws it at his opponent. At the time of projection, the stone is 150 cm above the ground and has a speed of 3 m/s. Calculate the work done by the demonstrator during the process. If it takes one second for the demonstrator to lift the stone and throw it, what horsepower does he use? 


A small block of mass 200 g is kept at the top of a frictionless incline which is 10 m long and 3⋅2 m high. How much work was required (a) to lift the block from the ground and put it an the top, (b) to slide the block up the incline? What will be the speed of the block when it reaches the ground if (c) it falls off the incline and drops vertically to the ground (d) it slides down the incline? Take g = 10 m/s2


A simple pendulum of length L with a bob of mass m is deflected from its rest position by an angle θ and released (following figure). The string hits a peg which is fixed at a distance x below the point of suspension and the bob starts going in a circle centred at the peg. (a) Assuming that initially the bob has a height less than the peg, show that the maximum height reached by the bob equals its  initial height. (b) If the pendulum is released with \[\theta = 90^\circ \text{ and x = L}/2\] , find the maximum height reached by the bob above its lowest position before the string becomes slack. (c) Find the minimum value of x/L for which the bob goes in a complete circle about the peg when the pendulum is released from \[\theta = 90^\circ \]


Figure ( following ) shows a smooth track which consists of a straight inclined part of length l joining smoothly with the circular part. A particle of mass m is projected up the incline from its bottom. Find the minimum projection-speed \[\nu_0\] for which the particle reaches the top of the track.


Figure ( following ) shows a smooth track which consists of a straight inclined part of length l joining smoothly with the circular part. A particle of mass m is projected up the incline from its bottom.Assuming that the projection-speed is only slightly greater than \[\nu_0\] , where will the block lose contact with the track?


A chain of length l and mass m lies on the surface of a smooth sphere of radius R > l with one end tied to the top of the sphere.  Find the tangential acceleration \[\frac{d\nu}{dt}\] of the chain when the chain starts sliding down.

 

An electron and a proton are moving under the influence of mutual forces. In calculating the change in the kinetic energy of the system during motion, one ignores the magnetic force of one on another. This is because ______.


A bullet of mass m fired at 30° to the horizontal leaves the barrel of the gun with a velocity v. The bullet hits a soft target at a height h above the ground while it is moving downward and emerges out with half the kinetic energy it had before hitting the target.

Which of the following statements are correct in respect of bullet after it emerges out of the target?

  1. The velocity of the bullet will be reduced to half its initial value.
  2. The velocity of the bullet will be more than half of its earlier velocity.
  3. The bullet will continue to move along the same parabolic path.
  4. The bullet will move in a different parabolic path.
  5. The bullet will fall vertically downward after hitting the target.
  6. The internal energy of the particles of the target will increase.

Give example of a situation in which an applied force does not result in a change in kinetic energy.


Suppose the average mass of raindrops is 3.0 × 10–5 kg and their average terminal velocity 9 ms–1. Calculate the energy transferred by rain to each square metre of the surface at a place which receives 100 cm of rain in a year.


A particle moves in one dimension from rest under the influence of a force that varies with the distance travelled by the particle as shown in the figure. The kinetic energy of the particle after it has travelled 3 m is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×