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Question
A cylinder rolls on a horizontal place surface. If the speed of the centre is 25 m/s, what is the speed of the highest point?
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Solution
Let vc be the translational velocity of the cylinder.
Let ω be the rotational velocity of the cylinder.
Let r be the radius of the cylinder.
For rolling, we have
vc = rω
Speed of the highest point = vc + rω = 2vc
\[\Rightarrow2 \times 25\text{ m/s}=50\text{ m/s}\]
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