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A Cylinder Rolls on a Horizontal Place Surface. If the Speed of the Centre is 25 M/S, What is the Speed of the Highest Point?

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प्रश्न

A cylinder rolls on a horizontal place surface. If the speed of the centre is 25 m/s, what is the speed of the highest point?

बेरीज
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उत्तर

Let vc be the translational velocity of the cylinder.

Let ω be the rotational velocity of the cylinder.

Let r be the radius of the cylinder.

For rolling, we have

vc = 

Speed of the highest point = vc + rω = 2vc

\[\Rightarrow2 \times 25\text{ m/s}=50\text{ m/s}\]

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पाठ 10: Rotational Mechanics - Exercise [पृष्ठ १९९]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
पाठ 10 Rotational Mechanics
Exercise | Q 70 | पृष्ठ १९९

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