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Question
A current of 0.15 A flows through the filament of a bulb with a resistance of 400 Ω. The p.d. of the electric supply is:
Options
120 V
60 V
80 V
100 V
MCQ
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Solution
60 V
Explanation:
Using Ohm's law, V = IR
= 0.15 × 400
= 60 V
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