Question

A current of 0.15 A flows through the filament of a bulb with a resistance of 400 Ω. The p.d. of the electric supply is:

पर्याय

• 120 V

• 60 V

• 80 V

• 100 V

Answer 1

60 V

Explanation:

Using Ohm's law, V = IR

= 0.15 × 400

= 60 V