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Question
A convex lens has:
Options
Negative power (\[f < 0\])
Negative power (\[f > 0\])
Positive power (\[f > 0\])
Positive power (\[f < 0\])
MCQ
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Solution
For a convex (converging) lens the focal length is positive, \[f > 0\], and since \[P = \frac{1}{f}\], its power is positive.
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