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A Company Manufactures Two Types of Novelty Souvenirs Made of Plywood. Souvenirs of Type a Require 5 Minutes Each for Cutting and 10 Minutes Each for Assembling.

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Question

A company manufactures two types of novelty souvenirs made of plywood. Souvenirs of type A
require 5 minutes each for cutting and 10 minutes each for assembling. Souvenirs of type B require 8 minutes each for cutting and 8 minutes each for assembling. There are 3 hours and 20 minutes available  for cutting and 4 hours available for assembling. The profit is Rs. 50 each for type A and Rs. 60 each  for type B souvenirs. How many souvenirs of each type should the company manufacture in order to  maximize profit? Formulate the above LPP and solve it graphically and also find the maximum profit. 

Sum
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Solution 1

Let no.of souvenirs of type A to be manufactured = x 

Type B = y. 

Type 

Quant.  Profit  Cutting time A.T 
A x 50 5min  10min
B y 60 8min  8min

Total time for cutting = 3h 20min
                                   =  200min
Total time for Assembling = 240 min
Profit =  50x +  60y (this is obj function)
5x + 8y ≤ 200               .....(i)
10x + 8y ≤ 240            .....(ii)
Also x, y ≥ 0

Corner points  Value of objective
O(0,0) 0
B(8 , 20)  400 + 1200 = 1600
A(0 , 25) 

1500

C (24 , 0)  1200

So the maximum profit is obtained by producing 8 units of A and 20 units of B  And max. profit is Rs. 1600

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Solution 2

Let the company manufacture x souvenirs of type A and y souvenirs of type B. Therefore,
x ≥ 0 and y ≥ 0
The given information can be complied in a table as follows.

  Type A Type B Availability
Cutting (min) 5 8 3 x 60 + 20 = 200
Assembling (min) 10 8 4 x 60 = 240

The profit on type A souvenirs is Rs 50 and on type, B souvenirs is Rs 60. Therefore, the constraints are i.e.,
5x + 8y ≤ 200.
10x + 8y ≤ 240 i.e., 5x + 4y ≤ 120
Total profit, Z = 50x + 60y

The mathematical formulation of the given problem is
Maximize Z = 50x + 60y ..… (1)
subject to the constraints,
5x + 8y ≤ 200   ..… (2)
5x + 4y ≤ 120   ..… (3)
x, y ≥ 0 ..… (4)

The feasible region determined by the system of constraints is as follows.

The corner points are A (24, 0), B (8, 20), and C (0, 25).
The values of Z at these corner points are as follows.

Corner point  Z = 50x + 60y  
A (24, 0) 1200  
B (8, 20) 1600 → Maximum
C (0, 25) 1500  

The maximum value of Z is 1600 at (8, 20).

Thus, 8 souvenirs of type A and 20 souvenirs of type B should be produced each day to get the maximum profit of Rs 1600.

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2018-2019 (March) 65/3/3

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