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Question
A coin is places at the bottom of a beaker containing water (refractive index = 4/3) to a depth of 12 cm. By what height the coin appears to be raised when seen from vertically above?
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Solution
Refractive index of the water, 𝛍w = 4/3
Real depth at which the coin is places = 12 cm
Shift in the image = ?
Shift = `"real depth"xx(1-1/µ)`
Shift= `12(1-3/4)`
R=12/4=3 cm
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|
S. No. |
Angle of incidence |
Angle of refraction |
Angle of emergence |
|
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|
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|
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40° |
|
IV |
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