Question

A child has a die whose 6 faces show the letters given below: 

\[\boxed{\text{A}}\]\[\boxed{\text{B}}\]\[\boxed{\text{C}}\]\[\boxed{\text{A}}\]\[\boxed{\text{A}}\]\[\boxed{\text{B}}\]

The die is thrown once. What is the probability of getting (i) A and (ii) B?

Answer 1

In a single throw of a die, the possible outcomes are:

A, B, C, A, A, B

Total number of possible outcomes = 6

(i) Let E₁ be the event of getting A.

Number of favourable outcomes = 3

∴ P(getting A) =  P(E₁) =  `3/6` = `1/2`

(ii) Let E₂ be the event of getting B.

Number of favourable outcomes = 2

∴ P(getting B) =  P(E₂) =  `2/6` = `1/3`