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Question
A charge of 5000 C flows through an electric circuit in 2 hours and 30 minutes. Calculate the magnitude of current in a circuit.
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Solution
Charge = Q = 5000 C
Time = t = 2 houe 30 minutes
t = 2 × 60 + 30 = 150 min
t = 150 × 60 second
t = 9000 second
Electric current = I = ?
I = `"Q"/"t"`
I = `5000/9000 = 0.555` A
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