Advertisements
Advertisements
Question
A charge of 5000 C flows through an electric circuit in 2 hours and 30 minutes. Calculate the magnitude of current in a circuit.
Advertisements
Solution
Charge = Q = 5000 C
Time = t = 2 houe 30 minutes
t = 2 × 60 + 30 = 150 min
t = 150 × 60 second
t = 9000 second
Electric current = I = ?
I = `"Q"/"t"`
I = `5000/9000 = 0.555` A
APPEARS IN
RELATED QUESTIONS
Explain the mechanism of attraction of iron nails by a magnet when brought near them.
In a uniform magnetic field, the field lines are:
Define the isoclinic line.
Describe two methods of determining the arrangement of the lines of force in the field close to a bar magnet. Give a brief explanation of each method.
Draw diagram showing the arrangement of the lines of force for a piece of soft iron laid in line with the magnetic field.
The relative strength of the magnetic field at a point in the space surrounding the magnet is shown by the ____________.
A magnetic needle is kept in a non-uniform magnetic field. It experiences ______.
The relation between weber and Tesla is ______.
