Advertisements
Advertisements
Question
A charge of 8860 C flows through an electric circuit in 2 min and 40 s. Calculate the magnitude of current in a circuit.
Advertisements
Solution
Charge = Q = 8860 C
Time = t = 2 min 40 s
t = (2 × 60 + 40)s
t = 160 s
Electric current = I = ?
I = `"Q"/"t" = 8860/160`
I = 55.375 A
RELATED QUESTIONS
Write symbol and state function of following component in an electric circuit :
ammeter
Explain the concept of electric potential difference in terms of work done in transferring the charge.
How electric current flows in liquids?
The following figure shows a metal rod PQ mounted on an insulated stand. The cap of an uncharged electroscope touches one end Q of the metal rod. A negatively charged ebonite rod is brought near the other end P of the metal rod.

(a) What charge does the end P have?
(b) What charge does the end Q have?
(c) What charge does the cap of the electroscope have?
(d) What charge does the gold leaf have?
(e) Will the leaf diverge or collapse? Give reason.
(f) If the electroscope is now earthed, what charge does the metal rod have?
A bulb is connected to a cell. How is the resistance of circuit affected if another identical bulb is connected (i) in series, (ii) in parallel, with the first bulb?
