Advertisements
Advertisements
Question
A charge of 8860 C flows through an electric circuit in 2 min and 40 s. Calculate the magnitude of current in a circuit.
Advertisements
Solution
Charge = Q = 8860 C
Time = t = 2 min 40 s
t = (2 × 60 + 40)s
t = 160 s
Electric current = I = ?
I = `"Q"/"t" = 8860/160`
I = 55.375 A
APPEARS IN
RELATED QUESTIONS
n electrons flow through a cross section of a conductor in time t. If charge on an electron is e, then write an expression for the current in the conductor.
In the electric circuit shown in Figure, label the parts A, B, C, D, E, and F. State the function of each part. Show in the diagram the direction of flow of current.

(a) Complete the circuit given in Fig. by inserting between the terminals A and C. an ammeter.
(b) In the diagram, mark the polarity at the terminals of ammeter and indicate clearly the direction of flow of current in the circuit when the circuit is complete.
(c) Name and state the purpose of Rh in the circuit.

State Ohm’s law.
How is the current flowing in a conductor changed if the resistance of conductor is doubled keeping the potential difference across it the same?
Name the physical quantity of which the unit is ohm
How is potential difference related to work done and quantity of charge?
What do you understand by the term series circuit?
Compare the brightness of two 60 watt bulbs.
When they are connected in parallel.
Explain giving scientific reasons.
