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Question
A charge of 1000 C flows through a conductor for 3 min and 20 s. Find the magnitude of current flowing through the conductor.
Numerical
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Solution
Charge (Q) = 1000 C, Time (t) = 3 min + 20 s = 200 s
Current (I) \[=\frac{\text{Q}}{\text{t}}\]
\[=\frac{1000 \text{~C}}{200 \text{~s}}\]
= 5.0 A
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