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Question
A block of Ag of mass x kg hanging from a string is immersed in a liquid of relative density 0.72. If the relative density of Ag is 10 and tension in the string is 37.12 N then compute the mass of Ag block.
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Solution
From the terminal velocity condition, FG – U = F F = T, m = x
`"mg" - "mg"((ρ_"w")/ρ)` = T
`"mg" [1 - 0.72/10]` = 37.12
9.8x [1 – 0.072] = 37.12
9.0944x = 37.12
x = 4 kg
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