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Question
A bag contains 6 red, 8 black and 4 white balls. A ball is drawn at random. What is the probability that ball drawn is not black?
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Solution
\[\text{ Number of red balls } = 6\]
\[\text{ Number of black balls }= 8 \]
\[\text{ Number of white balls } = 4\]
\[\text{ Total number of balls }= 6 + 8 + 4 = 18\]
\[ \therefore \text{ Total number of cases } = 18\]
\[\text{ Again, number of balls that are not black } = 18 - 8 = 10\]
\[\text{ Thus, the number of favourable cases is }10 . \]
\[ \therefore P\left( \text{ the drawn ball is not black }\right) = \frac{\text{ Number of favourable cases }}{\text{ Total number cases }} = \frac{10}{18} = \frac{5}{9}\]
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