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Question
A bag contains 5 red marbles, 8 white marbles, 4 green marbles. What is the probability that if one marble is taken out of the bag at random, it will be
not green
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Solution
\[\text{ Number of red marbles }= 5\]
\[\text{ Number of white marbles }= 8\]
\[\text{ Number of green marbles } = 4\]
\[\text{ Total number of marbles in the bag }= 5 + 8 + 4 = 17\]
\[ \therefore \text{ Total number outcomes }= 17\]
\[\text{ Let C be the event of drawing a green ball } . \]
\[ \therefore P\left( C \right) = \frac{\text{ Number of favourable outcomes }}{\text{ Total number of outcomes }} = \frac{4}{17}\]
\[\text{ Now, the event of not drawing a green ball is }: \]
\[P\left( C \right) = 1 - P\left( C \right) = 1 - \frac{4}{17} = \frac{13}{17}\]
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