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800 cm3 of gas is collected at 654 mm pressure. At what pressure would the volume of the gas reduce by 40% of its original volume, the temperature remaining constant?

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Question

800 cm3 of gas is collected at 654 mm pressure. At what pressure would the volume of the gas reduce by 40% of its original volume, the temperature remaining constant?

Numerical
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Solution

Given: V = 800 cm3

P = 654 mm

P1= ?

V1 = reduced volume = 40% of 800

= `(800 xx 40)/100`

= 320

Net V1 = 800 − 320 

= 480 cm3  

T = T1

Using the gas equation,

`(PV)/T = (P_1 V_1)/T_1`

`(800 xx 654)/T = (P_1 xx 480)/T_1`

Since T = T1

P1 = `(800 xx 654)/480`

= 1090 mm of Hg.

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Standard Temperature Pressure (S.T.P.)
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Chapter 7: Study of Gas Laws - Exercise 7 (B) [Page 126]

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Selina Concise Chemistry [English] Class 9 ICSE
Chapter 7 Study of Gas Laws
Exercise 7 (B) | Q 4 | Page 126

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