Question

From the equation

\[\ce{3Cu + 8HNO3 -> 3Cu(NO3)2 + 4H2O + 2NO}\]

(Atomic mass Cu = 64, H = 1, N = 14, O = 16)

Calculate the volume of nitric oxide at STP that can be collected.

Answer 1

504 g nitric acid reacts with 192 g of copper

∴ 63 g of nitric acid reacts with `192/504xx 63` = 24 g of copper

Hence, 24 g of copper is required.

504 g of nitric acid gives 2 × 22.4 litre volume of NO

∴ 63 g of nitric acid gives `(2xx22.4)/504 xx 63`

= 5.6 litres