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प्रश्न
From the equation
\[\ce{3Cu + 8HNO3 -> 3Cu(NO3)2 + 4H2O + 2NO}\]
(Atomic mass Cu = 64, H = 1, N = 14, O = 16)
Calculate the volume of nitric oxide at STP that can be collected.
संख्यात्मक
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उत्तर
504 g nitric acid reacts with 192 g of copper
∴ 63 g of nitric acid reacts with `192/504xx 63` = 24 g of copper
Hence, 24 g of copper is required.
504 g of nitric acid gives 2 × 22.4 litre volume of NO
∴ 63 g of nitric acid gives `(2xx22.4)/504 xx 63`
= 5.6 litres
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Standard Temperature Pressure (S.T.P.)
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