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∫4x(4x+4) dx

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Question

`int sqrt(4^x(4^x + 4))  "d"x`

Sum
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Solution

Let I = `int sqrt(4^x(4^x + 4))  "d"x`

= `int sqrt((2^x)^2 [(2^x)^2 + 4])  "d"x`

= `int sqrt((2^x)^2 + 2^2)*2^x  "d"x`

Put 2x = t

∴ 2x log2 dx = dt

∴ 2x dx = `1/(log 2)  "dt"`

∴ I = `1/(log 2) int sqrt("t"^2 + 2^2)  "dt"`

= `1/(log 2)["t"/2 sqrt("t"^2 + 2^2) + 2^2/2log |"t" + sqrt("t"^2 + 2^2)|] + "c"`

∴ I = `1/(log 2) [2^x/2 sqrt(4x + 4) + 2log |2^x + sqrt(4^x + 4)|] + "c"`

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Chapter 2.3: Indefinite Integration - Short Answers I

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