Advertisements
Advertisements
Question
3x + 23x2 + 6y2 + 2x + y2 + ______ = 5x + 7y2.
Advertisements
Solution
3x + 23x2 + 6y2 + 2x + y2 + –23x2 = 5x + 7y2.
Explanation:
Let (3x + 23x2 + 6y2 + 2x + y2) + M = 5x + 7y2
⇒ M = (5x + 7y2) – (3x + 23x2 + 6y2 + 2x + y2)
⇒ M = 5x + 7y2 – 3x – 23x2 – 6y2 – 2x – y2 ...[With –ve sign, +ve sign in the bracket will change on opening it]
⇒ M = 5x – 3x – 2x + 7y2 – 6y2 – y2 – 23x2
M = 0 + 0 – 23x2 = –23x2
APPEARS IN
RELATED QUESTIONS
Add : - 3a + 2b and 3a + b
Find the sum of: 4a2 + 5b2 – 6ab, 3ab, 6a2 – 2b2 and 4b2 – 5 ab
Find the sum of: – 4x2 and +7x
Enclose the given term in bracket as required:
x2 -y2 + z2 + 3x – 2y = x2 – (……..)
Find the numerical co-efficient of the following term:
2ab
The factors of a2 – 2ab + b2 are (a + b) and (a + b).
Common factor of 11pq2, 121p2q3, 1331p2q is 11p2q2.
Factorise the following expression.
2x2 – 2y + 4xy – x
Identify term and factor in the expression given below:
5y + 3y2
If (x2y + y2 + 3) is subtracted from (3x2y + 2y2 + 5), then coefficient of y in the result is ______.
