Advertisements
Advertisements
Question
3x + 23x2 + 6y2 + 2x + y2 + ______ = 5x + 7y2.
Advertisements
Solution
3x + 23x2 + 6y2 + 2x + y2 + –23x2 = 5x + 7y2.
Explanation:
Let (3x + 23x2 + 6y2 + 2x + y2) + M = 5x + 7y2
⇒ M = (5x + 7y2) – (3x + 23x2 + 6y2 + 2x + y2)
⇒ M = 5x + 7y2 – 3x – 23x2 – 6y2 – 2x – y2 ...[With –ve sign, +ve sign in the bracket will change on opening it]
⇒ M = 5x – 3x – 2x + 7y2 – 6y2 – y2 – 23x2
M = 0 + 0 – 23x2 = –23x2
APPEARS IN
RELATED QUESTIONS
Separate constant terms and variable terms from tile following:
8, x, 6xy, 6 + x, - 5xy2 , 15az2 , `(32"z")/"xy", "y"^2/"3x"`
In -5x3y2z4 ; write the coefficient of x3y. Also, write the degree of the given algebraic expression.
Subtract the second expression from the first:
x + 2y + z, - x - y - 3z
Enclose the given term in bracket as required:
x2 – xy2 – 2xy – y2 = x2 – (……..)
To add two like terms, its coefficients can be added
The coefficient of the term – 6x2y2 is – 6.
Factorise the following expression.
lx + my + mx + ly
Identify term which contain x and give the coefficient of x.
13y2 − 8yx
Identify term and factor in the expression given below:
5y + 3y2
If (x2y + y2 + 3) is subtracted from (3x2y + 2y2 + 5), then coefficient of y in the result is ______.
