Advertisements
Advertisements
Question
\[\sqrt[3]{125 \times 27} = 3 \times . . .\]
Advertisements
Solution
5
\[\sqrt[3]{125 \times 27} = 3 \times 5 \]
∵ \[\sqrt[3]{125 \times 27} = \sqrt[3]{125} \times \sqrt[3]{27} = \sqrt[3]{5 \times 5 \times 5} \times \sqrt[3]{3 \times 3 \times 3}\]
\[ = 5 \times 3\]
\[= 3 \times 5\] ( Commutative law )
APPEARS IN
RELATED QUESTIONS
You are told that 1331 is a perfect cube. Can you guess without factorization what is its cube root? Similarly, guess the cube roots of 4913, 12167, 32768
Using the method of successive subtraction examine whether or not the following numbers is perfect cube 1331 .
\[\sqrt[3]{. . .} = \sqrt[3]{4} \times \sqrt[3]{5} \times \sqrt[3]{6}\]
\[\sqrt[3]{\frac{512}{. . .}} = \frac{8}{13}\]
Evaluate:
\[\sqrt[3]{96} \times \sqrt[3]{144}\]
Find The cube root of the numbers 3048625, 20346417, 210644875, 57066625 using the fact that 20346417 = 9261 × 2197 .
Making use of the cube root table, find the cube root
7342 .
Making use of the cube root table, find the cube root
37800 .
Making use of the cube root table, find the cube root
7532 .
Using prime factorisation, find which of the following are perfect cubes.
1331
