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Question
2 kg of water at 100°C is contained in a vessel of negligible heat capacity. Into this water is added 3 kg of ice at 0°C. Calculate the amount of water at 0°C at the end of the experiment.
[Take SHC of water = 4.2 × 103 J kg−1°C−1 and SLH of ice = 336 × 103 J kg−1]
Numerical
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Solution
The heat given out by the hot water as it cools to 0°C:
Q = mcΔT
= 2 × 4.2 × 103 × 100
= 840000 J
Mass of melted ice $$(m) = \frac{Q}{L}$$
$$= \frac{840000}{336 \times 10^3}$$
= 2.5 kg
Total mass (m) = Mass of original water + Mass of melted ice
= 2 + 2.5
= 4.5 kg
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