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Chapters
2: Banking
3: Shares and dividends
4: Linear inequations
5: Quadratic equations
6: Factorisation of polynomials
7: Ratio and proportion
8: Matrices
9: Arithmetic and geometric progression
Chapter 10: Reflection
11: Section formula
12: Equation of a line
▶ 13: Similarity
14: Locus
15: Circles
16: Constructions
17: Mensuration
Chapter 18: Trigonometric identities
19: Trigonometric tables
20: Heights and distances
21: Measures of central tendency
22: Probability
•: Competency focused practice questions
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Solutions for Chapter 13: Similarity
Below listed, you can find solutions for Chapter 13 of CISCE Nootan for माठेमटिक्स [इंग्रजी] इयत्ता १० आयसीएसई.
Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता १० आयसीएसई 13 Similarity Exercise 13A [Pages 274 - 278]
State which pairs of triangles in the figures given below are similar. Write the similarity criterion used, and also write the pairs of similar triangles in symbolic form:
State which pair of triangles in the figure given below is similar. Write the similarity criterion used, and also write the pair of similar triangles in symbolic form.

State which pair of triangles in the figure given below is similar. Write the similarity criterion used, and also write the pair of similar triangles in symbolic form.

State which pair of triangles in the figure given below is similar. Write the similarity criterion used, and also write the pair of similar triangles in symbolic form.

In the following figure, AB || DC, AB = 6 cm, AE = 3 cm, CE = 4 cm, ED = 8 cm, determine BE and CD.

If ΔАВС ~ ΔEDF and given that AB = 5 cm, BC = 6.25 cm, DF = 15 cm, and EF = 16.8 cm, find AC and DE.
If ΔАВС ~ ΔDEF, DE = 6 cm, EF = 9 cm, FD = 12 cm and AB = 3 cm, then find the perimeter of ΔAВС.
In the following figure, DE || BC and `(AD)/(DB) = 3/4`. If AC = 8.4 cm, find EC.

In the following figure, AB = 9 cm, CD = 6 cm and CM = 4 cm. Find AM.

In the following figure, DE || BC, AD = 4 cm, AB = 10 cm, BC = 12 cm, and AE = 6 cm, find AC and DE.

In the following figure, ∠ ACB = ∠ CDA. If AD = 6 cm and BD = 18 cm, find AC.

In the following figure, ABCD is a trapezium in which AB || DC. The diagonals AC and DB intersect at O.
- Prove that ΔOAB ∼ ΔОСD
- If OA = 3x − 1, OB = 2x + 1, OC = x + 3 and OD = 5x + 1, find the value of x.

In the following figure, ∠ACB = ∠AMN. Prove that ΔAMN ∼ ΔАСВ.

In the following figure, ∠BAD = ∠ACD. Prove that DA2 = CD × BD.

The diagonals of trapezium PQRS intersect each other at O. Prove that: `(PO)/(OR) = (QO)/(OS)`

In the following figure, DE || AC and `(BE)/(EC) = (BC)/(CF)`, prove that DC || AF.

In the following figure, ABCD is a trapezium in which AB || DC. E and F are points on AD and BC, respectively, such that EF || CD. Prove that `(AE)/(ED) = (BF)/(FC)`

From the mid-point M of the side CD of a parallelogram ABCD, the line BM is drawn, intersecting AC at L and AD, produced at E. Prove that EL = 2BL.

In the given figure, ∠PQR = ∠PRQ and QR × PR = QT × SQ. Show that ΔPQS ~ ΔTOR.

In the following figure, D is the mid-point of BC, and PQ || BC. Prove that AD bisects PQ.

In the following figure, ∠ABD = ∠CDB = ∠EFD = 90°. If AB = x, CD = y, EF = z, prove that `1/z = 1/x + 1/y`:

In the following figure, AB || EF || CD. If AB = 7.5 cm, CD = 4.5 cm, EC = 3 cm, EF = x and BE = y, find x and y.

A 15-meter-high tower casts a shadow of 24 meters long at a certain time. At the same time, a pole casts a shadow 40 meters long. Find the height of the pole.
In the following figure, BQ and CP are the altitudes on AC and AB, respectively. Prove that:
- BP × OQ = CQ × OP
- ΔРОQ − ΔВОС

In the following figure, DE || BC and DC || FE. Prove that AD2 = AB × AF.

In the following figure: DE || AQ and DF || AR. Prove that EF || QR.

In quadrilateral ABCD, the diagonals AC and BD intersect each other at point O. If AO = 2CO and BO = 2DO, show that OA × OD = OB × OC.
In quadrilateral ABCD, the diagonals AC and BD intersect each other at point O. If AO = 2CO and BO = 2DO, show that: ΔAOB is similar to ΔCOD.
In the following figure, medians AD and BE of ΔABC meet at point G and DF || BE. Prove that: EF = FC

In the following figure, medians AD and BE of ΔABC meet at point G and DF || BE. Prove that: AG : GD = 2 : 1

In the following figure, AB = AC and AB2 = BD × CE. Prove that ΔADB ~ ΔЕАС.

In the following figure, AD is the median of ΔABC. The bisectors of ∠ADB and ∠ADC meet AB and AC in points E and F, respectively. Prove that: EF || ВС.

In the following figure, A, B and C are points on OP, OQ and OR, respectively, such that AB || PQ and AC || PR. Show that BC || QR.

ABCD is a quadrilateral in which AB = AD, the bisector of ∠BAC and ∠CAD intersect the sides BC and CD at the points E and F, respectively. Prove that EF || BD.
Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता १० आयसीएसई 13 Similarity Exercise 13B [Pages 287 - 288]
If ΔABC and ΔDEF are similar and AB : DE = 5 : 4, find the ratio of the area of ΔАBC and the area of ΔDEF.
The ratio of the areas of two similar triangles is 49 : 100. Find the ratio of the lengths of their corresponding sides.
The area of ΔABC is 9 cm2, and the area of ΔDEF = 16 cm2. If ΔABC ~ ΔDEF, find: AB : DE.
The area of ΔABC is 9 cm2, and the area of ΔDEF = 16 cm2. If ΔABC ~ ΔDEF, find: perimeter (ΔABC) : perimeter (ΔABC).
The ratio between the areas of two similar triangles is 64 : 49. Find the ratio between their corresponding medians.
The ratio between the areas of two similar triangles is 64 : 49. Find the ratio between their corresponding altitudes.
ΔABC and ΔEDB are two similar triangles such that BD = `1/2 BC`. If ar(ΔАВC) = 400 cm2, find the area (ΔEDB).
In ΔPQR, MN is parallel to QR and `(PM)/(MQ) = 2/3`
- Find `(MN)/(QR)`.
- Prove that ΔOMN and ΔORQ are similar.
- Find the area of ΔOMN : Area of ΔORQ.

PQR is a triangle. S is a point on the side QR of ΔPQR such that ∠PSR = ∠QPR. Given QP = 8 cm, PR = 6 cm and SR = 3 cm.
- Prove ΔPQR ∼ ΔSPR.
- Find the lengths of QR and PS.
- Find `(Area of ΔPQR)/(Area of ΔSPR)`

In ΔABC, ∠ABC = ∠DAC, AB = 8 cm, AC = 4 cm and AD = 5 cm.
- Prove that ΔACD is similar to ΔBCA.
- Find BC and CD.
- Find the area of ΔACD : area of ΔABC.

D, E and F are respectively the mid-points of sides AB, BC and CA of ΔABC. Find the ratio of the area of ΔDEF and ΔABC.
In the given figure, ABC and CEF are two triangles where BA is parallel to CE and AF : AC = 5 : 8.
- Prove that ΔADF ∼ ΔCEF.
- Find AD if CE = 6 cm.
- If DF is parallel to BC, find the area of ΔADF : area of ΔABC.
In the given diagram, ΔADB and ΔACB are two right-angled triangles with ∠ADB = ∠BCA = 90°. If AB = 10 cm, AD = 6 cm, BC = 2.4 cm and DP = 4.5 cm.

- Prove that ΔAPD ∼ ΔBPC
- Find the length of BD and PB
- Hence, find the length of PA
- Find area ΔAPD : area ΔBPC.
Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता १० आयसीएसई 13 Similarity Exercise 13C [Page 289]
The model of a building is constructed with a scale factor of 1 : 30.
- If the height of the model is 80 cm, find the actual height of the building in metres.
- If the actual volume of a tank at the top of the building is 27 m3, find the volume of the tank on the top of the model.
On a map drawn to a scale of 1 : 2,50,000, a triangular plot of land has the following measurements:
AB = 3 cm, BC = 4 cm, ∠ABC = 90°.
Calculate:
- The actual length of AB in km.
- The area of the plot in sq. km.
On a map drawn to a scale of 1 : 25000, a rectangular plot of land, ABCD, is measured as AB = 12 cm and BC = 16 cm. Calculate the diagonal distance of the plot in km and the plot area in km2.
A model of a high-rise building is made to a scale of 1 : 50.
- If the height of the model is 0.8 m, find the height of the actual building.
- If the floor area of a flat in the building is 20 m2, find the floor area of that in the model.
The scale of a map is 1 : 200000. A plot of land of area 20km2 is to be represented on the map. Find: The number of kilometres on the ground represented by 1 cm on the map.
The scale of a map is 1 : 200000. A plot of land of area 20km2 is to be represented on the map. Find: The area in km2 that can be represented by 1 cm2
Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता १० आयसीएसई 13 Similarity Exercise 13D [Pages 290 - 291]
Multiple Choice Questions
Choose the correct answer from the given four options in each of the following questions:
In the given figure ∠BAP = ∠DCP = 70°, PC = 6 cm and CA = 4 cm, then PD : DB is ______.

5 : 3
3 : 5
3 : 2
2 : 3
In the given figure, AP = `1/2 PB`, then ar(ΔAPQ) : ar(ΔABC) is ______.

1 : 9
9 : 1
1 : 4
4 : 1
If ΔABC ~ ΔDEF and ar(ΔABC) : ar(ΔDEF) = 25 : 4, then BC : EF is ______.
3 : 2
2 : 3
5 : 2
2 : 5
ΔАВС ~ ΔРQR, ar(ΔABC) = 16 cm2, ar(ΔPQR) = 144 cm2 and PQ = 6 cm, then the length of BA is ______.
1 cm
2 cm
3 cm
4 cm
In the given figure, DE || BC and `(AD)/(DB) = 2/5`. If AC = 5.6 cm, then EC is equal to ______.

1.4 cm
2.8 cm
3.6 cm
4 cm
In the given figure, ΔАВС ~ ΔRPQ, then ∠Q is equal to ______.

70°
60°
50°
80°
In the given figure, AE || DC. If AB = 6 cm, BC = 4 cm, and AE = 9 cm, then DC is equal to ______.

6 cm
5 cm
4 cm
3 cm
If ΔАBC ~ ΔPQR, PQ = 5 cm, perimeter of ΔPQR = 20 cm, AB = 7.5 cm, then perimeter of ABC is ______.
25 cm
30 cm
24 cm
32 cm
∆ABC and ∆BDE are two equilateral triangles such that D is the mid-point of BC. The ratio of the areas of triangles ABC and BDE is ______.
2 : 1
1 : 2
4 : 1
1 : 4
Solutions for 13: Similarity
![Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता १० आयसीएसई chapter 13 - Similarity Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता १० आयसीएसई chapter 13 - Similarity - Shaalaa.com](/images/mathematics-english-class-10-icse_6:8d4d7165de72474d81faa9e5f82aa90d.jpg)
Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता १० आयसीएसई chapter 13 - Similarity
Shaalaa.com has the CISCE Mathematics माठेमटिक्स [इंग्रजी] इयत्ता १० आयसीएसई CISCE solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. Nootan solutions for Mathematics माठेमटिक्स [इंग्रजी] इयत्ता १० आयसीएसई CISCE 13 (Similarity) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.
Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. Nootan textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.
Concepts covered in माठेमटिक्स [इंग्रजी] इयत्ता १० आयसीएसई chapter 13 Similarity are Similarity of Triangles (Corresponding Sides & Angles), Criteria for Similarity of Triangles, Basic Proportionality Theorem, Similarity as a Size Transformation, Applications to Maps and Models, Relation Between the Areas of Two Triangles, Similarity and Congruency of Figures.
Using Nootan माठेमटिक्स [इंग्रजी] इयत्ता १० आयसीएसई solutions Similarity exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in Nootan Solutions are essential questions that can be asked in the final exam. Maximum CISCE माठेमटिक्स [इंग्रजी] इयत्ता १० आयसीएसई students prefer Nootan Textbook Solutions to score more in exams.
Get the free view of Chapter 13, Similarity माठेमटिक्स [इंग्रजी] इयत्ता १० आयसीएसई additional questions for Mathematics माठेमटिक्स [इंग्रजी] इयत्ता १० आयसीएसई CISCE, and you can use Shaalaa.com to keep it handy for your exam preparation.
