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Chapters
2: Banking
3: Shares and dividends
4: Linear inequations
5: Quadratic equations
6: Factorisation of polynomials
▶ 7: Ratio and proportion
8: Matrices
9: Arithmetic and geometric progression
Chapter 10: Reflection
11: Section formula
Chapter 12: Equation of a line
Chapter 13: Similarity
14: Locus
15: Circles
16: Constructions
17: Mensuration
Chapter 18: Trigonometric identities
Chapter 19: Trigonometric tables
Chapter 20: Heights and distances
Chapter 21: Measures of central tendency
Chapter 22: Probability
Chapter •: Competency focused practice questions
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Solutions for Chapter 7: Ratio and proportion
Below listed, you can find solutions for Chapter 7 of CISCE Nootan for माठेमटिक्स [इंग्रजी] इयत्ता १० आयसीएसई.
Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता १० आयसीएसई 7 Ratio and proportion Exercise 7A [Page 116]
Find the ratio compounded at 2 : 3, 4 : 5, 5 : 6
Find the ratio compounded at a : b, b : c, c : d
Find the ratio compounded at x + y : x − y, x3 − y3 : x2 − y2
Find the duplicate ratio of 4 : 7
Find the duplicate ratio of m : n
Find the duplicate ratio of 5x : 6y
Find the sub-duplicate ratio of 49 : 81.
Find the sub-duplicate ratio of 16x4 : 25y4.
Find the sub-duplicate ratio of 169m6 : 196n6.
Find the triplicate ratio of 3 : 5.
Find the triplicate ratio of x : y.
Find the triplicate ratio of 2x : 3y.
Find the sub-triplicate ratio of a9 : b12.
Find the sub-triplicate ratio of 64a3 : 343b6.
Find the reciprocal ratio of 3 : 4.
Find the reciprocal ratio of 42 : 52.
Find the reciprocal ratio of `1/3 : 4`
If 4x + 3 : 7x − 1 be the duplicate ratio of 3 : 4, find the value of x.
If a : b be the triplicate ratio of (a + x) : (b + x), prove that x3 − 3abx − ab(a + b) = 0.
Find which is greater?
`3/4 or 15/16`
Find which is greater?
2 : 3 or 3 : 4
If x : y = 7 : 12, find the value of 3x + 5y : 6x + 7y.
If x : y = 3 : 4, find the ratio of 3y − x : 2x + y.
If 3x + 2y : 5x + 6y = 1 : 2, find the ratio of x : y.
If 5a + 3b : 3a + 5b = 3 : 4, find a : b.
What number must be added to each terms of the ratio 14 : 23 so that it may becomes equal to 8 : 11?
Two numbers are in the ratio of 3 : 4. If 4 be added to each, the ratio becomes 4 : 5, find the numbers.
If A : B = 3 : 4, B : C = 2 : 5, find A : B : C.
If A : B = 5 : 2, B : C = 3 : 4, find A : C.
If 6A = 3B = 5C, find A : B : C.
If (4x2+ xy) : (3xy – y2) = 12 : 5, find (2x + y) : (x + 2y).
If m : n is the duplicate ratio of m + x : n + x; show that x2 = mn.
If `(5x + 4y)/(8x + 5y) = 2/3`, find the value of 4x + 7y : 9x + 2y.
Two numbers are in the ratio of 2 : 3, and if 6 subtracted from each, the remainders are in the ratio of 4 : 9. Find them.
If `x/y = 3(1)/3`, find the value of `(x - 3y)/(2x - 5y)`.
A’s present age is to B’s present age as 8 : 7. 27 years ago their ages were 5 : 4. Find their present ages.
If `a/b = 2/3` and `x/y = 3/4`, find the value of `(4ay - 3bx)/(5ax - 2by)`.
Two numbers are in the ratio of 3 : 5 and the sum of their squares is 1666. Find them.
The ratio between A and B’s share is 7 : 11. If B’s share is ₹ 22.55, find A’s share.
A bag contains ₹ 102 in the form of ₹ 1,50 paise and 25 paise coins in the ratio of 16 : 5 : 28. Find the number of coins of each kind.
In a mixture of 28 litres, the ratio of milk and water is 5 : 2. Another 2 litres of water is added to the mixture. Find the ratio of milk and water in the new mixture.
The ages of two persons are in the ratio of 5 : 7. Sixteen years ago, they were in the ratio 3 : 5. Find their present age.
Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता १० आयसीएसई 7 Ratio and proportion Exercise 7B [Pages 125 - 126]
State whether the following are in proportion:
6 : 18 :: 5 : 15
State whether the following are in proportion:
3 : 7.5 :: 2 : 7
State whether the following are in proportion:
10 : 21 :: 4 : 8.4
State whether the following are in proportion:
9 : 12 :: 12 : 16
State whether the following are in proportion:
11 : 13 :: 4 : 5
Find the fourth proportional to the following:
11, 15, 33
Find the fourth proportional to the following:
1.5, 4.5, 3.5
Find the fourth proportional to the following:
`1/2, 1/3, 1/4`
Find the fourth proportional to the following:
`1/7, 1/5, 1(1)/7`
Find the value of x in the following:
₹ 10 : ₹ 25 = 14m : x
Find the value of x in the following:
75 : 15 = x : 7
Find the value of x in the following:
x : 7.5 = 7 : 17.5
Find the third proportional to the following:
20, 15
Find the third proportional to the following:
2.4, 3.6
Find the third proportional to the following:
`2(2)/3 m`, 4m
Find the third proportional to the following:
3, 12
Find the mean proportional of the following:
9, 25
Find the mean proportional of the following:
`1/16, 4/25`
Find the mean proportional of the following:
17.5, 0.007
Find the mean proportional of the following:
0.25, 40000
Find the mean proportional of the following:
₹ 5, ₹ 125
Find the mean proportional of the following:
2x, 8x
Find the mean proportional of the following:
`(a - b)/(a + b) and (a^2b^2)/(a^2 - b^2)`
What number must be added to each of the numbers 4, 6, 8, 11 in order to get the four numbers in proportion?
What number must be added to each of the numbers 6, 15, 20 and 43 to make them proportional?
What least number must be subtracted from each of the numbers 7, 17 and 47 so that the remainders are in continued proportion?
The following numbers, K + 3, K + 2, 3K – 7 and 2K – 3 are in proportion. Find k.
k + 6 is the mean proportion between k − 2 and k2. Find the value of k.
What number must be added to each of the numbers 6, 14 and 30 so that the resulting numbers may be in continued proportion?
Find two numbers such that their mean proportional is 28 and third proportional in 224.
Find two numbers such that their mean proportional is 12 and third proportional in 96.
If `a/b = c/d` then prove that each of the given ratio is equal to `(3a + 2c)/(3b + 2d)`.
If `a/b = c/d` then prove that each of the given ratio is equal to `sqrt((4a^2 - 3c^2)/(4b^2 - 3d^2))`.
If `a/b = c/d` then prove that each of the given ratio is equal to `root3 ((a^3 + 4c^3)/(b^3 + 4d^3))`.
If `a/b = c/d` then prove that `(5a + 3b)/(5c + 3d) = ((4a^3 - 3b^3)/(4c^3 - 3d^3))^(1/3)`
If `a/b = c/d` then prove that `(6a + 7b)/(6c + 7d) = sqrt((5a^2 + 3b^2)/(5c^2 + 3d^2))`
If b is the mean proportional between a and c, prove that a, c, a² + b², and b² + c² are proportional.
If a + c = mb and `1/b + 1/d = m/c`, prove that a, b, c and d are in proportion.
If `x/a = y/b = z/c`, prove that: `(x^2a^2 + y^2b^2 + z^2c^2)/(a^3x + b^3y + c^3z) = ((xyz)/(abc))^(1/3)`
If `x/a = y/b = z/c`, prove that: `x^3/a^3 + y^3/b^3 + z^3/c^3 = (3xyz)/(abc)`
If `a/b = c/d = e/f`, prove that: (a2 + c2 + e2) (b2 + d2 + f2) = (ab + cd + ef)2
If `a/b = c/d = e/f`, prove that: `(a^2 + c^2)^3/(b^2 + d^2)^3 = e^6/f^6`
If `a/b = c/d = e/f`, prove that: `a^2/b^2 + c^2/d^2 + e^2/f^2 = (ac)/(bd) + (ce)/(df) + (ae)/(bf)`
If b is the mean proportional between a and c, show that `(a^4 + a^2b^2 + b^4)/(b^4 + b^2c^2 + c^4) = a^2/c^2`.
If ax = by = cz, prove that `(yz)/x^2 + (zx)/y^2 + (xy)/z^2 = a^2/(bc) + b^2/(ca) + c^2/(ab)`
If a, b, c, d are in proportion, prove that (2a + 3b) (3c + 5d) = (2c + 3d) (3a + 5b)
If a, b, c, d are in proportion, prove that (a2 + c2) : (b2 + d2) = ac : bd
If a, b, c, d are in proportion, prove that `(a^2 - ab + b^2)/(c^2 - cd + d^2) = (a^2 - b^2)/(c^2 - d^2)`
If a, b, c, d are in proportion, prove that `(a + c)^3/(b + d)^3 = (a^2(a - c))/(b^2(b - d))`.
If a, b, c, d are in proportion, prove that abcd(a−2 + b−2 + c−2 + d−2) = a2 + b2 + c2 + d2.
If x, y, z are in continued proportion, prove that: `(x + y)^2/(y + z)^2 = x/z`.
If x, y, z are in continued proportion, prove that: `(px^2 + qxy + ry^2)/(py^2 + qyz + rz^2) = x/z`.
If x, y and z are in continued proportion, Prove that:
`x/(y^2.z^2) + y/(z^2.x^2) + z/(x^2.y^2) = 1/x^3 + 1/y^3 + 1/z^3`
If x, y, z are in continued proportion, prove that: x2y2z2(x−4 + y−4 + z−4) = y−2(x4 + y4 + z4)
If x, y, z are in continued proportion, prove that: xyz(x + y + z)3 = (xy + yz + zx)3.
If a, b, c, d are in continued proportion, prove that: `sqrt(ab) + sqrt(bc) - sqrt(cd) = sqrt((a + b - c)(b + c - d))`.
If a, b, c, d are in continued proportion, prove that: (a + d)(b + c) – (a + c)(b + d) = (b – c)2
If a, b, c, d are in continued proportion, prove that: (a2 + b2) (c2 + d2) = (b2 + c2)2.
If a, b, c, d are in continued proportion, prove that: `(a^3 + b^3 + c^3)/(b^3 + c^3 + d^3) = a/d`
If a, b, c, d are in continued proportion, prove that: `((a - b)/c + (a - c)/b)^2 - ((d - b)/c + (d - c)/b)^2 = (a - d)^2 (1/c^2 - 1/b^2)`.
Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता १० आयसीएसई 7 Ratio and proportion Exercise 7C [Pages 138 - 140]
If `x/y = p/q`, prove that `(5x + 7y)/(5x - 7y) = (5p + 7q)/(5p - 7q)`.
If `a/b = c/d`, prove that `(4a + 9b)/(4a - 9b) = (4c + 9d)/(4c - 9d)`.
If a : b :: c : d, show that (2a + 3b) : (2c + 3d) :: (2a − 3b) : (2c − 3d).
If `(3x + 4y)/(3a + 4b) = (3x - 4y)/(3a - 4b),` prove that `x/y = a/b`.
If `(8a - 5b)/(8c - 5d) = (8a + 5b)/(8c + 5d)`, prove that `a/b = c/d.`
If (6a + 5b) (6c − 5d) = (6a − 5b) (6c + 5d), prove that a, b, c, d are in proportion.
If (9a2 + 8b2) (9c2 − 8d2) = (9a2 − 8b2) (9c2 + 8d2), prove that a : b :: c : d.
If (xa + yb) : b :: (xc + yd) : d, prove that a : b :: c : d.
If x = `(2ab)/(a + b)`, prove that `(x + a)/(x - a) + (x + b)/(x - b)` = 2
If x = `(8ab)/(a + b)`, prove that `(x + 4a)/(x - 4a) + (x + 4b)/(x - 4b)` = 2
Using properties of proportion solve for x, given
`(sqrt(5x)+sqrt(2x -6))/(sqrt(5x)- sqrt(2x -6)) = 4`
Using properties of proportion, find the value of x from the following:
`(sqrt(1 + x) + sqrt(1 - x))/(sqrt(1 + x) - sqrt(1 - x)) = a/b`
Using properties of proportion, find the value of x from the following:
`(a + sqrt(a^2 - 2ax))/(a - sqrt(a^2 - 2ax))` = b
Using properties of proportion, find the value of x from the following:
`(sqrt(12x + 1) + sqrt(2x - 3))/(sqrt(12x + 1) - sqrt(2x - 3)) = 3/2`
Using properties of proportion, solve for x. Given that x is positive:
`(2x + sqrt(4x^2 -1))/(2x - sqrt(4x^2 - 1)) = 4`
Using properties of proportion, find the value of x from the following:
`(3x + sqrt(9x^2 - 5))/(3x - sqrt(9x^2 - 5))` = 5
If x = `(sqrt(2a + 3b) + sqrt(2a - 3b))/(sqrt(2a + 3b) - sqrt(2a - 3b))` then show that 3bx2 − 4ax + 3b = 0.
If x = `(sqrt(b^2 + ab) + sqrt(b^2 - ab))/(sqrt(b^2 + ab) - sqrt(b^2 - ab))` show that ax2 − 2bx + a = 0.
Solve for x: `16((a - x)/(a + x))^3 = (a + x)/(a - x)`
If x = `(sqrt(2a + 1) + sqrt(2a - 1))/(sqrt(2a + 1) - sqrt(2a - 1))` prove that x2 − 4ax + 1 = 0
Using properties of proportion, find x : y, if `(x^2 + 2x)/(2x + 4) = (y^2 + 3y)/(3y + 9)`
If `(x^2 + y^2)/(x^2 - y^2) = 17/8`, then find the value of:
- x : y
- `(x^3 + y^3)/(x^3 - y^3)`
Solve for x: `(1 + x + x^2)/(1 - x + x^2) = (62(1 + x))/(63(1 - x))`
Given `x = (sqrt(a^2 + b^2) + sqrt(a^2 - b^2))/(sqrt(a^2 + b^2) - sqrt(a^2 - b^2)`. Use componendo and dividendo to prove that: `b^2 = (2a^2x)/(x^2 + 1)`
If `(x + y)/(ax + by) = (y + z)/(ay + bz) = (z + x)/(az + bx)`, prove that each of these ratio is equal to `(2)/(a + b)` unless x + y + z = 0.
If `(b + c - a)/(y + z - x) = (c + a - b)/(z + x - y) = (a + b - c)/(x + y - z)` then prove that each ratio is equal to `a/x = b/y = c/z`
Using the properties of proportion, solve for x, given. `(x^4 + 1)/(2x^2) = (17)/(8)`.
If `(a + b)^3/(a - b)^3 = 64/27`
- Find `(a + b)/(a - b)`
- Hence using properties of proportion, find a : b.
Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता १० आयसीएसई 7 Ratio and proportion Exercise 7D [Pages 140 - 141]
Choose the correct answer from the given four options in each of the following questions:
x, 8, 16 are in continued proportion. The value of x is ______.
2
4
5
6
The mean proportional of two numbers is 16 and the third proportional is 128. The larger number is ______.
24
48
32
64
If b is the mean proportional of a and c then the mean proportional of a2 + b2 and b2 + c2 is ______.
a + b + c
ab + cа
ca + cb
ab + bc
If 3x + 4y : 3x − 4y = 17 : 1 then x : y is equal to ______.
2 : 3
3 : 2
2 : 5
5 : 2
The sub-triplicate ratio of 125 : 27 is ______.
25 : 9
9 : 25
3 : 5
5 : 3
The quantity added to each term of the ratio 6 : 11 so that it becomes equal to 3 : 4 is ______.
8
9
12
14
If x, y, z are in continued proportion then `(x^2 + y^2)/(y^2 + z^2)` is equal to ______.
`x/z`
`x/y`
`y/z`
`y/x`
If A : B = 2 : 3, В : C = 4 : 5 then A : B : C is equal to ______.
8 : 12 : 15
6 : 9 : 10
8 : 12 : 25
None of these
If a : b = 3 : 11 then (15a – 3b) : (9a + 5b) is equal to ______.
35 : 6
6 : 35
6 : 41
41 : 6
If `(1 + x + x^2)/(1 - x + x^2) = (62(1 + x))/(63(1 - x))` then the value of x is ______.
`1/5`
5
3
`1/3`
The given table shows the distance covered and the time taken by a train moving at a uniform speed along a straight track:
| Distance (in m) | 60 | 90 | y |
| Time (in sec) | 2 | x | 5 |
The values of x and y are:
x = 4, y = 150
x = 3, y = 100
x = 4, y = 100
x = 3, y = 150
Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता १० आयसीएसई 7 Ratio and proportion Exercise 7E [Page 141]
Valid Statements Questions
In the following question, two statements (i) and (ii) are given. Choose the valid statement.
- The duplicate ratio of `sqrt2 : sqrt3` is 2 : 3
- 7 : 8 > 4 : 5
Only (i)
Only (ii)
Both (i) and (ii)
Neither (i) nor (ii)
In the following question, two statements (i) and (ii) are given. Choose the valid statement.
- If (4a + 3b) : (6a +7b) = 16 : 25 then a : b = 31 : 4.
- If (1 + x) : (3x + 1) is the duplicate ratio of 3 : 5 then x = 8.
Only (i)
Only (ii)
Both (i) and (ii)
Neither (i) nor (ii)
In the following question, two statements (i) and (ii) are given. Choose the valid statement.
- The third proportional of 5, 10 is 40.
- If three quantities are in continued proportion, then first is to the third is the sub-duplicate ratio of first to the second.
Only (i)
Only (ii)
Both (i) and (ii)
Neither (i) nor (ii)
In the following question, two statements (i) and (ii) are given. Choose the valid statement.
- If x : y = 2 : 3, y : z = 4 : 5, then x : y : z = 8 : 12 : 15.
- lf x, 2, 8, y are in continued proportion, then x = 1.
Only (i)
Only (ii)
Both (i) and (ii)
Neither (i) nor (ii)
Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता १० आयसीएसई 7 Ratio and proportion Chapter Test [Page 143]
Using componendo and dividendo solve for x:
`(sqrt(2x + 2) + sqrt(2x - 1))/(sqrt(2x + 2) - sqrt(2x - 1))` = 3
If `a/c = c/d = e/f` prove that: `(a^3 + c^3)^2/(b^3 + d^3)^2 = e^6/f^6`
If 3A = 4B = 6C, find: A : B : C.
If (4x2 + xy) : (3xy – y2) = 12 : 5, find (x + 2y) : (2x + y).
If `(by + cz)/(b^2 + c^2) = (cz + ax)/(c^2 + a^2) = (ax + by)/(a^2 + b^2)`, prove that each of these ratio is equal to `x/a = y/b = z/c`
If x = `(root3 (a + 1) + root3 (a - 1))/(root3 (a + 1) - root(3)(a - 1)`, prove that x³ – 3ax² + 3x – a = 0.
Find x from the equation: `(a+ x + sqrt(a^2 - x^2))/(a + x - sqrt(a^2 - x^2)) = b/x`
If x = `"pab"/(a + b)`, prove that `(x + pa)/(x - pa) - (x + pb)/(x - pb) = (2(a^2 - b^2))/(ab)`.
If x = `(2mab)/(a + b)`, find the value of `(x + ma)/(x - ma) + (x + mb)/(x - mb)`.
If (3x2 + 2y2) : (3x2 − 2y2) = 11 : 9, find the value of `(3x^4 + 25y^4)/(3x^4 - 25y^4)`.
If a : b = 9 : 10, find the value of `(5a + 3b)/(5a - 3b)`
If a : b = 9 : 10, find the value of `(2a^2 - 3b^2)/(2a^2 + 3b^2)`
If `x/(b + c - a) = y/(c + a - b) = z/(a + b - c)` prove that each ratio’s equal to `(x + y + z)/(a + b + c)`.
If x : a = y : b, prove that `(x^4 + a^4)/(x^3 + a^3) + (y^4 + b^4)/(y^3 + b^3) = ((x + y)^4 + (a + b)^4)/((x+ y)^3 + (a + b)^3`
If `x/a = y/b = z/c`, prove that `(3x^3 - 5y^3 + 4z^3)/(3a^3 - 5b^3 + 4c^3) = ((3x - 5y + 4z)/(3a - 5b + 4c))^3`.
Solutions for 7: Ratio and proportion
![Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता १० आयसीएसई chapter 7 - Ratio and proportion Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता १० आयसीएसई chapter 7 - Ratio and proportion - Shaalaa.com](/images/mathematics-english-class-10-icse_6:8d4d7165de72474d81faa9e5f82aa90d.jpg)
Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता १० आयसीएसई chapter 7 - Ratio and proportion
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Concepts covered in माठेमटिक्स [इंग्रजी] इयत्ता १० आयसीएसई chapter 7 Ratio and proportion are Ratio, Proportion, Direct Applications of Ratio and Proportion, Ratio in Lowest Terms, All About Ratios: Dividing, Comparing, and Modifying Quantities, Commensurable and Incommensurable Quantities, Composition of Ratios, Concept of Continued Proportion, Properties of Proportion.
Using Nootan माठेमटिक्स [इंग्रजी] इयत्ता १० आयसीएसई solutions Ratio and proportion exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in Nootan Solutions are essential questions that can be asked in the final exam. Maximum CISCE माठेमटिक्स [इंग्रजी] इयत्ता १० आयसीएसई students prefer Nootan Textbook Solutions to score more in exams.
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