मराठी

What least number must be subtracted from each of the numbers 7, 17 and 47 so that the remainders are in continued proportion? - Mathematics

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प्रश्न

What least number must be subtracted from each of the numbers 7, 17 and 47 so that the remainders are in continued proportion?

What number must be subtracted from each of number 7, 17, 47 so that the remainder may be in continued proportion?

बेरीज
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उत्तर

Let the number subtracted be x.

∴ (7 – x) : (17 – x) :: (17 – x)(47 – x)

⇒ `(7 - x)/(17 - x) = (17 - x)/(47 - x)`

⇒ (7 – x) (47 – x) = (17 – x) (17 – x)

Left side:

7 × 47 − 7x − 47x + x2 = 329 − 54x + x2

Right side:

(17−x)2 = 289 − 34x + x2

⇒ 329 − 54x + x2 = 289 − 34x + x2

⇒ 329 − 54x = 289 − 34x

⇒ 329 – 289 = 54x − 34x

⇒ 40 = 20x

⇒ x = `20/40`

⇒ x = 2

Thus, the required number which should be subtracted is 2.

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Ratio and proportion - Exercise 7B [पृष्ठ १२५]

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नूतन Mathematics [English] Class 10 ICSE
पाठ 7 Ratio and proportion
Exercise 7B | Q 8. | पृष्ठ १२५
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