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प्रश्न
Write the mechanism of the reaction of HI with methoxymethane.
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उत्तर
The reaction between methoxymethane and HI is:
\[\ce{CH3 - O - CH3 + HI -> CH3I + CH3OH}\]
Step 1: Generation of oxonium ion: Protonation of the ether molecule.
Step 2: Nucleophilic attack on oxonium ion:
If excess HI is used, the methanol formed above reacts with HI to form methyl iodide.
संबंधित प्रश्न
Write the main product(s) in each of the following reactions:
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\[\ce{CH3 - CH2 - CH2 - O - CH3 + HBr ->}\]
Predict the product of the following reaction:
\[\ce{(CH3)3C - OC2H5 ->[HI]}\]
Show how will you synthesize cyclohexylmethanol using an alkyl halide by an SN2 reaction.
Write the equation of the reaction of hydrogen iodide with 1-propoxypropane.
Write the equation of the reaction of hydrogen iodide with methoxybenzene.
Explain the fact that in aryl alkyl ethers
- the alkoxy group activates the benzene ring towards electrophilic substitution and
- it directs the incoming substituents to ortho and para positions in the benzene ring.
Write the formula of reagents used in the following reactions :
Bromination of phenol to 2,4,6-tribromophenol
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Hydroboration of propene and then oxidation to propanol.
Write the structures of the main products in the following reactions :
The ether
when treated with HI produces:
Indicate the σ and π bond in the following molecule:
HCONHCH3
Consider the following reaction
Identify products A and B:-
