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प्रश्न
Which is the last element in the series of the actinoids? Write the electronic configuration of this element. Comment on the possible oxidation state of this element.
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उत्तर
The last element of the actinoid series is Lawrencium (Lr) which has an atomic number of 103. Its electronic configuration is [Rn] 5f146d17s2 and its possible oxidation state is +3.
संबंधित प्रश्न
Distinguish between lanthanoid and actinoids.
How would you account for the following:
The chemistry of actinoids is more complicated as compared to lanthanoids.
How would you account for the following:
Actinoid contraction is greater than lanthanoid contraction.
With reference to structural variability and chemical reactivity, write the differences between lanthanoids and actinoids
Compare the chemistry of the actinoids with that of lanthanoids with reference to electronic configuration
Compare the chemistry of the actinoids with that of lanthanoids with reference to oxidation states
Write four points of distinction between Lanthanoids and Actinoids.
What is the position of actinoids in periodic table ?
How would you account the following :
Highest fluoride of Mn is MnF4 whereas the highest oxide is Mn2O7.
Give reasons for the following:
The chemistry of actinoids elements is not so smooth as that of the lanthanoids.
Which of the following actinoids exhibits only + 3 oxidation state?
Identify the CORRECT statement.
Which among the following actinoids exhibits highest oxidation state +7?
Which of the following properties is NOT of actinoids?
Which of the following actinoids show oxidation states upto +7?
(i) Am
(ii) Pu
(iii) U
(iv) Np
What is actinoid contraction?
What are actinoids? Give their general electronic configuration.
