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प्रश्न
What type of bonding would you expect between Hydrogen and Chlorine?
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उत्तर
Hydrogen and chlorine react to form (HCl) by covalent bonding. Hydrogen contains one electron in its outermost shell and chlorine also contains one electron in its outermost shell. So the hydrogen and chlorine atoms share one electron from each atom to attain stability.
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संबंधित प्रश्न
State the reason to explain why covalent compounds "have low melting and boiling points."
How does graphite act as a lubricant?
Fill in the blank in the following sentence:
Two atoms of the same element combine to form a molecule. The bond between them is known as ................ bond.
Explain why, ionic compounds conduct electricity in solution whereas covalent compounds do not conduct electricity.
A hydrocarbon having one double bond has 100 carbon atoms in its molecule. The number of hydrogen atoms in its molecule will be
(a) 200
(b) 198
(c) 202
(d) 196
State the type of bonding in the following molecule.
Ammonium ion
Give two example in following case:
Liquid non polar compounds
Draw an electron dot structure of the following molecule. (Without showing the circle) :
Ethene
Explain the following term with example.
Alkane
The covalent bond in which the electrons are shared equally between the combining atoms.
Explain the following briefly:
Cl2 is a non polar molecule, while HCl is a polar molecule.
Explain the structure of Hydronium ion.
Explain the following:
Covalent compounds have low melting and boiling point.
Name a greenish-yellow gas which also bleaches.
Answer the following question.
What is methane? Draw its electron dot structure. Name the type of bonds formed in this compound. Why are such compounds:
(i) poor conductors of electricity? and
(ii) have low melting and boiling points? What happens when this compound burns in oxygen?
Explain covalent bond with example.
Complete the following activity.
Write the names of the hydrocarbons for the following structural formula.
(isobutylene, cyclohexane, propene, cyclohexene, cyclopentane, benzene, propyne, isobutane, propane)
| \[\begin{array}{cc}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\ |\phantom{....}|\phantom{....}|\\\ce{H - C - C - C - H}\\ |\phantom{....}|\phantom{....}|\\\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H} \end{array}\] |
Carbon forms four covalent bonds by sharing its four valence electrons with four univalent atoms, e.g., hydrogen. After the formation of four bonds, carbon attains the electronic configuration of ______.
The table shows the electronic structures of four elements.
| Element | Electronic Structure |
| P | 2, 6 |
| Q | 2, 8, 1 |
| R | 2, 8, 7 |
| S | 2, 8, 8 |
- Identify which element(s) will form covalent bonds with carbon.
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State the reasons, why carbon cannot
- Lose four electrons to form C4+ cation and
- Gain four electrons to form C4- anion.
How does carbon overcome this problem to form compounds?
