मराठी

What is Meant by Negative Deviation from Raoult'S Law? Give an Example. What is the Sign of ∆Mixh for Negative Deviation?

Advertisements
Advertisements

प्रश्न

What is meant by negative deviation from Raoult's law? Give an example. What is the sign of ∆mixH for negative deviation?

Advertisements

उत्तर

The non-ideal solutions that do not obey Raoult's law over the entire range of concentration and have vapour pressures lower than those predicted by Raoult's law show a negative deviation from Raoult's law.

Example: A mixture of chloroform and acetone

In case of solutions showing negative deviations, ΔmixH has a negative sign.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
2014-2015 (March) Foreign Set 2

संबंधित प्रश्‍न

In non-ideal solution, what type of deviation shows the formation of maximum boiling azeotropes?


The vapour pressure of water is 12.3 kPa at 300 K. Calculate vapour pressure of 1 molal solution of a non-volatile solute in it.


Calculate the mass of a non-volatile solute (molar mass 40 g mol−1) which should be dissolved in 114 g octane to reduce its vapour pressure to 80%.


Benzene and toluene form ideal solution over the entire range of composition. The vapour pressure of pure benzene and toluene at 300 K are 50.71 mm Hg and 32.06 mm Hg respectively. Calculate the mole fraction of benzene in vapour phase if 80 g of benzene is mixed with 100 g of toluene.


Some liquids on mixing form 'azeotropes'. What are 'azeotropes'?


At equilibrium the rate of dissolution of a solid solute in a volatile liquid solvent is ______.


The boiling point of an azeotropic mixture of water and ethanol is less than that of water and ethanol. The mixture shows ____________.


Using Raoult’s law explain how the total vapour pressure over the solution is related to mole fraction of components in the following solutions.

\[\ce{CHCl3(l) and CH2Cl2(l)}\]


Using Raoult’s law explain how the total vapour pressure over the solution is related to mole fraction of components in the following solutions.

\[\ce{NaCl(s) and H2O(l)}\]


The correct option for the value of vapour pressure of a solution at 45°C with benzene to octane in a molar ratio of 3 : 2 is

[At 45°C vapour pressure of benzene is 280 mm Hg and that of octane is 420 mm Hg. Assume Ideal gas]


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×