Advertisements
Advertisements
प्रश्न
What is the area of a triangle with base 4.8 cm and height 3.6 cm?
Advertisements
उत्तर
We have the base of a triangle = 4.8 cm
Height of a triangle = 3.6 cm
∴ Area of a triangle = `1/2` × base × height
= `1/2xx4.8xx3.6`
= `(4.8xx3.6)/2`
= `17.28/2`
= 8.64 cm2
संबंधित प्रश्न
Find the equation of the line joining (1, 2) and (3, 6) using the determinants.
If area of triangle is 35 sq. units with vertices (2, −6), (5, 4) and (k, 4), then k is ______.
ΔABC is right angled at A (see the given figure). AD is perpendicular to BC. If AB = 5 cm, BC = 13 cm and AC = 12 cm, Find the area of ΔABC. Also find the length of AD.
Find the area of a triangle whose sides are 9 cm, 12 cm and 15 cm ?
If G(-2, 1) is the centroid of a ΔABC and two of its vertices are A(1, -6) and B(-5, 2) , find the third vertex of the triangle.
For what value of k(k>0) is the area of the triangle with vertices (-2, 5), (k, -4) and (2k+1, 10) equal to 53 square units?
Find a relation between x and y, if the points A(2, 1), B(x, y) and C(7,5) are collinear.
The coordinates of the point P dividing the line segment joining the points A (1, 3) and B (4, 6) in the ratio 2 : 1 are:
Find the area of the trapezium PQRS with height PQ given in the following figure.
Area of a triangle = `1/2` base × ______.
