Advertisements
Advertisements
प्रश्न
In the following figure, ΔMNO is a right-angled triangle. Its legs are 6 cm and 8 cm long. Length of perpendicular NP on the side MO is ______.
पर्याय
4.8 cm
3.6 cm
2.4 cm
1.2 cm
Advertisements
उत्तर
In the following figure, ΔMNO is a right-angled triangle. Its legs are 6 cm and 8 cm long. Length of perpendicular NP on the side MO is 4.8 cm.
Explanation:
Given, ΔMNO is a right angled triangle.
So, according to Pythagoras theorem,
MO2 = MN2 + NO2
= 62 + 82
= 36 + 64
⇒ MO2 = 100
⇒ MO = `sqrt(100)`
⇒ MO = 10 cm
∴ Area of ΔMNO = `1/2` × Base × Height
⇒ `1/2` × MN × NO = `1/2` × MO × NP
⇒ `1/2` × 6 × 8 = `1/2` × 10 × NP
⇒ NP = `24/5`
⇒ NP = 4.8 cm
APPEARS IN
संबंधित प्रश्न
Find the area of the triangle ABC with A(1, −4) and mid-points of sides through A being (2, −1) and (0, −1).
Find the area of a triangle whose vertices are A(3, 2), B (11, 8) and C(8, 12).
If the coordinates of two points A and B are (3, 4) and (5, – 2) respectively. Find the coordniates of any point P, if PA = PB and Area of ∆PAB = 10
Find the centre of a circle passing through the points (6, − 6), (3, − 7) and (3, 3).
Find the area of the following triangle:
Find the area of the following triangle:
If the coordinates of the mid-points of the sides of a triangle are (1, 1), (2, —3) and (3, 4), find the vertices of the triangle.
Show that the points A (3,1) , B (0,-2) , C(1,1) and D (4,4) are the vertices of parallelogram ABCD.
Show that the following points are collinear:
(i) A(2,-2), B(-3, 8) and C(-1, 4)
The area of a trapezium is 475 cm2 and the height is 19 cm. Find the lengths of its two parallel sides if one side is 4 cm greater than the other.
