Advertisements
Advertisements
प्रश्न
In the following figure, ΔMNO is a right-angled triangle. Its legs are 6 cm and 8 cm long. Length of perpendicular NP on the side MO is ______.
पर्याय
4.8 cm
3.6 cm
2.4 cm
1.2 cm
Advertisements
उत्तर
In the following figure, ΔMNO is a right-angled triangle. Its legs are 6 cm and 8 cm long. Length of perpendicular NP on the side MO is 4.8 cm.
Explanation:
Given, ΔMNO is a right angled triangle.
So, according to Pythagoras theorem,
MO2 = MN2 + NO2
= 62 + 82
= 36 + 64
⇒ MO2 = 100
⇒ MO = `sqrt(100)`
⇒ MO = 10 cm
∴ Area of ΔMNO = `1/2` × Base × Height
⇒ `1/2` × MN × NO = `1/2` × MO × NP
⇒ `1/2` × 6 × 8 = `1/2` × 10 × NP
⇒ NP = `24/5`
⇒ NP = 4.8 cm
APPEARS IN
संबंधित प्रश्न
median of a triangle divides it into two triangles of equal areas. Verify this result for ΔABC whose vertices are A (4, - 6), B (3, - 2) and C (5, 2).
Find the area of a triangle with vertices at the point given in the following:
(−2, −3), (3, 2), (−1, −8)
ΔABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm (see the given figure). The height AD from A to BC, is 6 cm. Find the area of ΔABC. What will be the height from C to AB i.e., CE?
Find the area of a triangle whose sides are respectively 150 cm, 120 cm and 200 cm ?
For what value of y, are the points P(1, 4), Q(3,y) and R(-3, 16) are collinear ?
Prove that the points A (a,0), B( 0,b) and C (1,1) are collinear, if `( 1/a+1/b) =1`.
The coordinates of the point P dividing the line segment joining the points A (1, 3) and B (4, 6) in the ratio 2 : 1 are:
Find the value(s) of k so that the quadratic equation x2 − 4kx + k = 0 has equal roots.
Show that the ∆ABC is an isosceles triangle if the determinant
Δ = `[(1, 1, 1),(1 + cos"A", 1 + cos"B", 1 + cos"C"),(cos^2"A" + cos"A", cos^2"B" + cos"B", cos^2"C" + cos"C")]` = 0
In the following figure, if PR = 12 cm, QR = 6 cm and PL = 8 cm, then QM is ______.
