Advertisements
Advertisements
प्रश्न
In the following figure, ΔMNO is a right-angled triangle. Its legs are 6 cm and 8 cm long. Length of perpendicular NP on the side MO is ______.

विकल्प
4.8 cm
3.6 cm
2.4 cm
1.2 cm
Advertisements
उत्तर
In the following figure, ΔMNO is a right-angled triangle. Its legs are 6 cm and 8 cm long. Length of perpendicular NP on the side MO is 4.8 cm.
Explanation:

Given, ΔMNO is a right angled triangle.
So, according to Pythagoras theorem,
MO2 = MN2 + NO2
= 62 + 82
= 36 + 64
⇒ MO2 = 100
⇒ MO = `sqrt(100)`
⇒ MO = 10 cm
∴ Area of ΔMNO = `1/2` × Base × Height
⇒ `1/2` × MN × NO = `1/2` × MO × NP
⇒ `1/2` × 6 × 8 = `1/2` × 10 × NP
⇒ NP = `24/5`
⇒ NP = 4.8 cm
APPEARS IN
संबंधित प्रश्न
If P(–5, –3), Q(–4, –6), R(2, –3) and S(1, 2) are the vertices of a quadrilateral PQRS, find its area.
Find the area of the triangle formed by joining the mid-points of the sides of the triangle whose vertices are (0, -1), (2, 1) and (0, 3). Find the ratio of this area to the area of the given triangle
The vertices of a ΔABC are A (4, 6), B (1, 5) and C (7, 2). A line is drawn to intersect sides AB and AC at D and E respectively, such that `(AD)/(AB) = (AE)/(AC) = 1/4`Calculate the area of the ΔADE and compare it with the area of ΔABC. (Recall Converse of basic proportionality theorem and Theorem 6.6 related to ratio of areas of two similar triangles)
Find the area of the following triangle:

Find the area of triangle whose vertices are (a, c + a), (a, c) and (–a, c – a).
For what value of k(k > 0) is the area of the triangle with vertices (–2, 5), (k, –4) and (2k + 1, 10) equal to 53 square units?
Find the area of ΔABC with vertices A(0, –1), B(2, 1) and C(0, 3). Also, find the area of the triangle formed by joining the midpoints of its sides. Show that the ratio of the areas of two triangles is 4 : 1.
If the points (3, -2), (x, 2), (8, 8) are collinear, then find the value of x.
Observe all the four triangles FAB, EAB, DAB and CAB as shown in the following figure.

- All triangles have the same base and the same altitude.
- All triangles are congruent.
- All triangles are equal in area.
- All triangles may not have the same perimeter.
Area of a triangle PQR right-angled at Q is 60 cm2 (see figure). If the smallest side is 8 cm long, find the length of the other two sides.

