Advertisements
Advertisements
प्रश्न
In ☐ABCD, l(AB) = 13 cm, l(DC) = 9 cm, l(AD) = 8 cm, find the area of ☐ABCD.

Advertisements
उत्तर

Draw perpendicular from C to line AB. Name the point E.
CE = AD = 8 cm
EB = AB − AE = AB − CD = 13 − 9 = 4cm
∴ Area of of a trapezium = `1/2 xx "sum of lengths of parallel sides" xx h`
A (☐ABCD) = `1/2 xx [l(AB) + l(DC)] xx l(AD)`
= `1/2 xx (13 + 9) xx 8`
= `1/2 xx 22 xx 8`
= 11 x 8
= 88 sq. cm
∴ The area of ☐ABCD is 88 sq. cm.
संबंधित प्रश्न
ABCD is a rectangle formed by joining the points A(–1, –1), B(–1, 4), C(5, 4) and D(5, –1). P, Q, R and S are the midpoints of AB, BC, CD and DA respectively. Is the quadrilateral PQRS a square? a rectangle? or a rhombus? Justify your answer.
Find the area of a triangle with vertices at the point given in the following:
(1, 0), (6, 0), (4, 3)
Find values of k if area of triangle is 4 sq. units and vertices are (−2, 0), (0, 4), (0, k).
Find the area of the following triangle:

Find a relation between x and y, if the points A(x, y), B(–5, 7) and C(–4, 5) are collinear.
The coordinates of the point P dividing the line segment joining the points A (1, 3) and B (4, 6) in the ratio 2 : 1 are:
The table given below contains some measures of the right angled triangle. Find the unknown values.
| Base | Height | Area |
| ? | 12 m | 24 sq.m |
A(6, 1), B(8, 2) and C(9, 4) are three vertices of a parallelogram ABCD. If E is the midpoint of DC, find the area of ∆ADE.
The points A(2, 9), B(a, 5) and C(5, 5) are the vertices of a triangle ABC right angled at B. Find the values of a and hence the area of ∆ABC.
Ratio of the area of ∆WXY to the area of ∆WZY is 3 : 4 (see figure). If the area of ∆WXZ is 56 cm2 and WY = 8 cm, find the lengths of XY and YZ.

