Advertisements
Advertisements
प्रश्न
What is the area of a triangle with base 4.8 cm and height 3.6 cm?
Advertisements
उत्तर
We have the base of a triangle = 4.8 cm
Height of a triangle = 3.6 cm
∴ Area of a triangle = `1/2` × base × height
= `1/2xx4.8xx3.6`
= `(4.8xx3.6)/2`
= `17.28/2`
= 8.64 cm2
संबंधित प्रश्न
The perimeter of a right triangle is 60 cm. Its hypotenuse is 25 cm. Find the area of the triangle.
median of a triangle divides it into two triangles of equal areas. Verify this result for ΔABC whose vertices are A (4, - 6), B (3, - 2) and C (5, 2).
The two opposite vertices of a square are (− 1, 2) and (3, 2). Find the coordinates of the other two vertices.
The vertices of a ΔABC are A (4, 6), B (1, 5) and C (7, 2). A line is drawn to intersect sides AB and AC at D and E respectively, such that `(AD)/(AB) = (AE)/(AC) = 1/4`Calculate the area of the ΔADE and compare it with the area of ΔABC. (Recall Converse of basic proportionality theorem and Theorem 6.6 related to ratio of areas of two similar triangles)
The point A divides the join of P (−5, 1) and Q(3, 5) in the ratio k:1. Find the two values of k for which the area of ΔABC where B is (1, 5) and C(7, −2) is equal to 2 units.
Show that the points A (3,1) , B (0,-2) , C(1,1) and D (4,4) are the vertices of parallelogram ABCD.
A(6,1) , B(8,2) and C(9,4) are the vertices of a parallelogram ABCD. If E is the midpoint of DC, find the area of ΔADE
Find the area of the following triangle:

A(6, 1), B(8, 2) and C(9, 4) are three vertices of a parallelogram ABCD. If E is the midpoint of DC, find the area of ∆ADE.
The area of ∆ABC is 8 cm2 in which AB = AC = 4 cm and ∠A = 90º.
