Advertisements
Advertisements
प्रश्न
What is the area of a triangle with base 4.8 cm and height 3.6 cm?
Advertisements
उत्तर
We have the base of a triangle = 4.8 cm
Height of a triangle = 3.6 cm
∴ Area of a triangle = `1/2` × base × height
= `1/2xx4.8xx3.6`
= `(4.8xx3.6)/2`
= `17.28/2`
= 8.64 cm2
संबंधित प्रश्न
Find the values of k so that the area of the triangle with vertices (1, -1), (-4, 2k) and (-k, -5) is 24 sq. units.
Find the area of a triangle with vertices at the point given in the following:
(2, 7), (1, 1), (10, 8)
Find the area of the following triangle:

Prove that the points (2a, 4a), (2a, 6a) and `(2a + sqrt3a, 5a)` are the vertices of an equilateral triangle.
The point A divides the join of P (−5, 1) and Q(3, 5) in the ratio k:1. Find the two values of k for which the area of ΔABC where B is (1, 5) and C(7, −2) is equal to 2 units.
prove that the points A (7, 10), B(-2, 5) and C(3, -4) are the vertices of an isosceles right triangle.
If A(5,2), B(2, -2) and C(-2, t) are the vertices of a right triangle with ∠B=90° , then find the value of t .
Show that the following points are collinear:
A(-5,1), B(5, 5) and C(10, 7)
Using determinants, find the area of ΔPQR with vertices P(3, 1), Q(9, 3) and R(5, 7). Also, find the equation of line PQ using determinants.
Find the missing value:
| Base | Height | Area of Triangle |
| ______ | 31.4 mm | 1256 mm2 |
