मराठी
तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएचएससी विज्ञान इयत्ता ११

What is meant by simple harmonic oscillation? Give examples and explain why every simple harmonic motion is a periodic motion whereas the converse need not be true. - Physics

Advertisements
Advertisements

प्रश्न

What is meant by simple harmonic oscillation? Give examples and explain why every simple harmonic motion is a periodic motion whereas the converse need not be true.

दीर्घउत्तर
Advertisements

उत्तर

Simple harmonic motion is a special type of oscillatory motion in which the acceleration or force on the particle is directly proportional to its displacement from a fixed point and is always directed towards that fixed point. In one dimensional case, let x be the displacement of the particle and ax be the acceleration of the particle, then

ax ∝ x .................(1)

ax = −bx ...............(2)

where b is a constant which measures acceleration per unit displacement and dimensionally it is equal to T-2.

By multiplying by the mass of the particle on both sides of equation (1) and from Newton’s second law, the force is

Fx = −kx ….........(3)

where k is a force constant which is defined as force per unit length. The negative sign indicates that displacement and force (or acceleration) are in opposite directions. This means that when the displacement of the particle is taken towards the right of equilibrium position (x takes positive value), the force (or acceleration) will point towards equilibrium (towards left) and similarly, when the displacement of the particle is taken towards left of equilibrium position (x takes negative value), the force (or acceleration) will point towards equilibrium (towards right). This type of force is known as restoring force because it always directs the particle executing simple harmonic motion to restore to its original (equilibrium or mean) position. This force (restoring force) is central and attractive whose center of attraction is the equilibrium position.

In order to represent in two or three dimensions, we can write using vector notation

`vec"F" = -"k"vec("r")` ...(4)

where `vec"r"` is the displacement of the particle from the chosen origin. Note that the force and displacement have a linear relationship. This means that the exponent of force `vec"F"` and the exponent of displacement `vec"r"` are unity. The sketch between cause (magnitude of force `vec|"F"|`) and effect (magnitude of displacement `vec|"r"|`) is a straight line passing through the second and fourth quadrant.

By measuring slope `1/"k"`, one can find the numerical value of force constant k.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 10: Oscillations - Evaluation [पृष्ठ २२०]

APPEARS IN

सामाचीर कलवी Physics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 10 Oscillations
Evaluation | Q III. 1. | पृष्ठ २२०

संबंधित प्रश्‍न

A particle in S.H.M. has a period of 2 seconds and amplitude of 10 cm. Calculate the acceleration when it is at 4 cm from its positive extreme position.


A body of mass 1 kg is made to oscillate on a spring of force constant 16 N/m. Calculate:

a) Angular frequency

b) frequency of vibration.


Hence obtain the expression for acceleration, velocity and displacement of a particle performing linear S.H.M.


In measuring time period of a pendulum, it is advised to measure the time between consecutive passage through the mean position in the same direction. This is said to result in better accuracy than measuring time between consecutive passage through an extreme position. Explain.


Which of the following quantities are always positive in a simple harmonic motion?


For a particle executing simple harmonic motion, the acceleration is proportional to


A spherical ball of mass m and radius r rolls without slipping on a rough concave surface of large radius R. It makes small oscillations about the lowest point. Find the time period.


A simple pendulum of length 40 cm is taken inside a deep mine. Assume for the time being that the mine is 1600 km deep. Calculate the time period of the pendulum there. Radius of the earth = 6400 km.


Consider the Earth as a homogeneous sphere of radius R and a straight hole is bored in it through its centre. Show that a particle dropped into the hole will execute a simple harmonic motion such that its time period is

T = `2π sqrt("R"/"g")`


A simple harmonic motion is given by, x = 2.4 sin ( 4πt). If distances are expressed in cm and time in seconds, the amplitude and frequency of S.H.M. are respectively, 


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×