Advertisements
Advertisements
प्रश्न
Two electric bulbs rated 100 W; 220 V and 60 W; 220 V are connected in parallel to electric mains of 220 V. Find the current drawn by the bulbs from the mains.
Advertisements
उत्तर
Firstly calculating the resistance of the electric bulbs,
P=`"V"^2/"R"`
⇒ `"R"="V"^2/"P"`
⇒ `"R"_1 =220^2/100 =484 Ω`
⇒ `"R"_2=220^2/60=2420/3 Ω`
`"R"_"eq" = ("R"_1"R"_2)/("R"_1+"R"_2)=(484xx(2420//3))/(484+(2420//3))=302.5Ω`
Total current drawn by the bulbs from the mains supply,
`"I"=220/302.5=0.73 "A"`
APPEARS IN
संबंधित प्रश्न
What is an Ammeter? How is It Connected in a Circuit? Draw a Diagram to Illustrate Your Answer.
A p.d. of 6 V is applied to two resistors of 3 Ω and 6 Ω connected in parallel. Calculate:
(a) the combined resistance
(b) the current flowing in the main circuit
(c) the current flowing in the 3 Ω resistor.
The rating of a fuse connected in the lighting circuit is:
(a) 15 A (b) 5 A (c) 10 A (d) Zero
A given wire of resistance 1 Ω is stretched to double its length. What will be its new resistance?
An electric bulb is rated 250 W, 230 V.
- the energy consumed in one hour, and
- the time in which the bulb will consume 1.0 kWh energy when connected to 230 V mains.
State the condition when it is advantageous to connect cells in series.
How should the electric lamps in a building be connected?
True or False – If False give the correct answer
The representation of the electric current is A
A current of 1 A is drawn by a filament of an electric bulb. Number of electrons passing through a cross section of the filament in 16 seconds would be roughly
