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प्रश्न
The temperature of a lead piece of mass 400 g rises from 20°C to 50°C when 1560 J of heat is supplied to it. Calculate Specific heat capacity of lead.
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उत्तर
Specific heat capacity of lead = `"Heat supplied"/("Mass" xx "Rise in temperature")`
`= (1560 "J")/((400 "g") xx (50^circ"C" - 20^circ "C")) = 0.13 "J"//"g"^circ "C"`
संबंधित प्रश्न
A solid of mass 50 g at 150 °C is placed in 100 g of water at 11 °C when the final temperature recorded is 20 °C. Find the specific heat capacity of the solid. (specific heat capacity of water = 4.2 J/g °C)
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Read the following paragraph and answer the questions.
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If heat is exchanged between a hot and cold object, the temperature of the cold object goes on increasing due to gain of energy and the temperature of the hot object goes on decreasing due to loss of energy. The change in temperature continues till the temperatures of both the objects attain the same value. In this process, the cold object gains heat energy and the hot object loses heat energy. If the system of both the objects is isolated from the environment by keeping it inside a heat resistant box (meaning that the energy exchange takes place between the two objects only), then no energy can flow from inside the box or come into the box. |
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(ii) Give one example to support your answer.
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