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प्रश्न
The temperature of a lead piece of mass 400 g rises from 20°C to 50°C when 1560 J of heat is supplied to it. Calculate Specific heat capacity of lead.
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उत्तर
Specific heat capacity of lead = `"Heat supplied"/("Mass" xx "Rise in temperature")`
`= (1560 "J")/((400 "g") xx (50^circ"C" - 20^circ "C")) = 0.13 "J"//"g"^circ "C"`
संबंधित प्रश्न
In an experiment on the specific heat of a metal, a 0.20 kg block of the metal at 150 °C is dropped in a copper calorimeter (of water equivalent 0.025 kg) containing 150 cm3 of water at 27 °C. The final temperature is 40 °C. Compute the specific heat of the metal. If heat losses to the surroundings are not negligible, is your answer greater or smaller than the actual value for the specific heat of the metal?
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