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प्रश्न
The molecules having dipole moment are:
(i) 2,2-Dimethylpropane
(ii) trans-Pent-2-ene
(iii) cis-Hex-3-ene
(iv) 2, 2, 3, 3 - Tetramethylbutane.
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उत्तर
(ii) trans-Pent-2-ene
(iii) cis-Hex-3-ene
Explanation:
Since, the +1 effect of CH2CH3 group is higher than that of CH3 group, therefore, the dipole moments of C – CH3 and C – CH2CH3 bonds are unequal. Although these two dipoles oppose each other, yet they do not exactly cancel out each other and hence trans-2-pentene has small but finite dipole moment.
In cis-hex-3-ene, although the dipole moments of the two C – CH2CH3 bond are equal, but they are inclined to each other at an angle of 60° and hence have a finite dipole moment.
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संबंधित प्रश्न
Write IUPAC name of the product obtained by the ozonolysis of the following compound:
2-Ethylbut-1-ene
What effect does branching of an alkane chain has on its boiling point?
What is the relationship between the members of following pairs of structures? Are they structural or geometrical isomers or resonance contributors?
\[\begin{array}{cc}
\ce{D}\phantom{......}\ce{H}\\
\backslash\phantom{......}/\\
\ce{C = C}\\
\phantom{...}/\phantom{......}\backslash\phantom{...}\\\ce{H}\phantom{.......}\ce{D}
\end{array}\]
\[\begin{array}{cc}
\ce{D}\phantom{......}\ce{D}\\
\backslash\phantom{......}/\\
\ce{C = C}\\
\phantom{...}/\phantom{......}\backslash\phantom{...}\\\ce{H}\phantom{.......}\ce{H}\end{array}\]
Find out the type of isomerism exhibited by the following pair.
CH3 – CH2 – NH – CH2 - CH3 and CH3 - NH - CH2 - CH2 - CH3
Find out the type of isomerism exhibited by the following pair.
\[\begin{array}{cc}
\ce{CH3 - CH - CH2 - CH3 and CH3 - CH2 - O - CH2 - CH3}\\|\phantom{...........................................}\\
\ce{OH}\phantom{.........................................}\end{array}\]
Find out the type of isomerism exhibited by the following pair.
Choose the correct option.
Which type of isomerism is possible in CH3 CHCHCH3?
But-1-ene and But-2-ene are examples of ____________.
The type of isomerism possible in 2-butene is ____________.
In which of the following, functional group isomerism is not possible?
Which of the following pairs are position isomers?
| I. | \[\begin{array}{cc} \phantom{.......................}\ce{O}\\ \phantom{.......................}||\\ \ce{CH3 - CH2 - CH2 - CH2 - C - H} \end{array}\] |
| II. | \[\begin{array}{cc} \phantom{.................}\ce{O}\\ \phantom{.................}||\\ \ce{CH3 - CH2 - CH2 - C - H} \end{array}\] |
| III. | \[\begin{array}{cc} \ce{CH3 - CH2 - C - CH2 - CH3}\\ \phantom{}||\\ \phantom{}\ce{O} \end{array}\] |
| IV. | \[\begin{array}{cc} \ce{CH3 - CH - CH2 - C - H}\\ \phantom{...}|\phantom{............}||\phantom{}\\ \phantom{...}\ce{CH3}\phantom{.........}\ce{O}\phantom{} \end{array}\] |
(i) I and II
(ii) II and III
(iii) II and IV
(iv) III and IV
Which of the following pairs are not functional group isomers?
| I. | \[\begin{array}{cc} \phantom{.......................}\ce{O}\\ \phantom{.......................}||\\ \ce{CH3 - CH2 - CH2 - CH2 - C - H} \end{array}\] |
| II. | \[\begin{array}{cc} \phantom{.................}\ce{O}\\ \phantom{.................}||\\ \ce{CH3 - CH2 - CH2 - C - H} \end{array}\] |
| III. | \[\begin{array}{cc} \ce{CH3 - CH2 - C - CH2 - CH3}\\ \phantom{}||\\ \phantom{}\ce{O} \end{array}\] |
| IV. | \[\begin{array}{cc} \ce{CH3 - CH - CH2 - C - H}\\ \phantom{...}|\phantom{............}||\phantom{}\\ \phantom{...}\ce{CH3}\phantom{.........}\ce{O}\phantom{} \end{array}\] |
(i) II and III
(ii) II and IV
(iii) I and IV
(iv) I and II
Consider structures I to VII and answer the question:
| I. | CH3 – CH2 – CH2 – CH2 – OH |
| II. | \[\begin{array}{cc} \ce{CH3 - CH2 - CH - CH3}\\ \phantom{.....}|\\ \phantom{.......}\ce{OH} \end{array}\] |
| III. | \[\begin{array}{cc} \phantom{...}\ce{CH3}\\ \phantom{}|\\ \ce{CH3 - C - CH3}\\ \phantom{}|\\ \phantom{..}\ce{OH} \end{array}\] |
| IV. | \[\begin{array}{cc} \ce{CH3 - CH - CH2 - OH}\\ |\phantom{........}\\ \ce{CH3}\phantom{......} \end{array}\] |
| V. | CH3 – CH2 – O – CH2 – CH3 |
| VI. | CH3 – O – CH2 – CH2 – CH3 |
| VII. | \[\begin{array}{cc} \ce{CH3 - O - CH - CH3}\\ \phantom{...}|\\ \phantom{......}\ce{CH3} \end{array}\] |
Identify the pairs of compounds that represents chain isomerism.
Compounds with same molecular formula but differing in their structures are said to be structural isomers. What type of structural isomerism is shown by
CH3 – S – CH2 – CH2 – CH3
And
\[\begin{array}{cc}
\phantom{.....................}\ce{CH3}\\
\phantom{................}/\\
\phantom{}\ce{CH3 - S - CH}\\
\phantom{...............}\backslash\\
\phantom{....................}\ce{CH3}
\end{array}\]
Assertion (A): Pent- 1- ene and pent- 2- ene are position isomers.
Reason (R): Position isomers differ in the position of functional group or a substituent.
Assertion (A): The compound cyclooctane has the following structural formula: 
It is cyclic and has conjugated 8π-electron system but it is not an aromatic compound.
Reason (R): (4n + 2)π electrons rule does not hold good and ring is not planar.
Tautomerism is exhibited by ______.
The compound which shows metamerism is ______
Which type of isomerism can not be shown by benzaldoxime?
Which one of the following pairs are called position isomers?
How many structural isomers possible of the molecular formula C3H6O (excluding enol form)?
The number of acyclic structural isomers (including geometrical isomers) for pentene are ______.
Compound with molecular formula C3H6O can show ______.
Which of the following pairs of compounds are positional isomers?
The number of geometrical isomers from [Co(NH3)3(NO2)3] is ______.
Which of the following pairs of compounds is an example of position isomerism?
