Advertisements
Advertisements
प्रश्न
The intensity of the electric field at a perpendicular distance of 0·5 m from an infinitely long line charge having linear charge density (λ) is 3-6 × 103 Vm-1. Find the value of λ.
Advertisements
उत्तर
λ =n E.2π∈0r where E =3.6 ×103 Vm-1, R= 5m
∴ λ = 3.6 × 103 ×05 ×2 ×3.14 × 8.85 ×10-12
= 3.6 × 103 ×3.14 ×8.85 ×10-12
= 100× 10-9
=10-7 Cm-1
∴ λ = 10-7 Cm-1
APPEARS IN
संबंधित प्रश्न
Why do the electrostatic field lines not form closed loops?
Why do the electric field lines never cross each other?
- An electrostatic field line is a continuous curve. That is, a field line cannot have sudden breaks. Why not?
- Explain why two field lines never cross each other at any point?
Two bar magnets are quickly moved towards a metallic loop connected across a capacitor ‘C’ as shown in the figure. Predict the polarity of the capacitor.
Draw the pattern of electric field lines, when a point charge –Q is kept near an uncharged conducting plate.
Explain why two field lines never cross each other at any point?
If Ea be the electric field strength of a short dipole at a point on its axial line and Ee that on the equatorial line at the same distance, then:
An electron enters an electric field with its velocity in the direction of the electric lines of force. Then ______
In figure, two positive charges q2 and q3 fixed along the y axis, exert a net electric force in the + x direction on a charge q1 fixed along the x-axis. If a positive charge Q is added at (x, 0), the force on q1
 (a) |
 (b) |
The magnitude of the electric field due to a point charge object at a distance of 4.0 m is 9 N/C. From the same charged object the electric field of magnitude, 16 N/C will be at a distance of ______.
