Advertisements
Advertisements
Question
The intensity of the electric field at a perpendicular distance of 0·5 m from an infinitely long line charge having linear charge density (λ) is 3-6 × 103 Vm-1. Find the value of λ.
Advertisements
Solution
λ =n E.2π∈0r where E =3.6 ×103 Vm-1, R= 5m
∴ λ = 3.6 × 103 ×05 ×2 ×3.14 × 8.85 ×10-12
= 3.6 × 103 ×3.14 ×8.85 ×10-12
= 100× 10-9
=10-7 Cm-1
∴ λ = 10-7 Cm-1
APPEARS IN
RELATED QUESTIONS
Why do the electrostatic field lines not form closed loops?
- An electrostatic field line is a continuous curve. That is, a field line cannot have sudden breaks. Why not?
- Explain why two field lines never cross each other at any point?
Which among the curves shown in the fig. cannot possibly represent electrostatic field lines?
(a)
(b)
(c)
(d)
(e)
(a) Derive an expression for the electric field E due to a dipole of length '2a' at a point distant r from the centre of the dipole on the axial line.
(b) Draw a graph of E versus r for r >> a.
(c) If this dipole were kept in a uniform external electric field E0, diagrammatically represent the position of the dipole in stable and unstable equilibrium and write the expressions for the torque acting on the dipole in both the cases.
Two bar magnets are quickly moved towards a metallic loop connected across a capacitor ‘C’ as shown in the figure. Predict the polarity of the capacitor.
Answer the following question.
Derive an expression for the electric field due to a dipole of dipole moment `vec"p"` at a point on its perpendicular bisector.
Explain why two field lines never cross each other at any point?
A point positive charge is brought near an isolated conducting sphere (figure). The electric field is best given by ______.
