Advertisements
Advertisements
प्रश्न
The figure shows the field lines on a positive charge. Is the work done by the field in moving a small positive charge from Q to P positive or negative? Give reason.
Advertisements
उत्तर
Work done = q.(potential at Q − potential at P), where q is the small positive charge
The electric potential at a point distant r due to the field created by a positive charge Q is given by
\[V = \frac{1}{4 \pi\epsilon_0}\frac{q}{r}\]
\[ \because r_P < r_Q \]
\[ \Rightarrow V_P > V_Q\]
APPEARS IN
संबंधित प्रश्न
- An electrostatic field line is a continuous curve. That is, a field line cannot have sudden breaks. Why not?
- Explain why two field lines never cross each other at any point?
Two bar magnets are quickly moved towards a metallic loop connected across a capacitor ‘C’ as shown in the figure. Predict the polarity of the capacitor.
A thin, metallic spherical shell contains a charge Q on it. A point charge q is placed at the centre of the shell and another charge q1 is placed outside it as shown in the following figure. All the three charges are positive. The force on the central charge due to the shell is ______.
The intensity of the electric field at a perpendicular distance of 0·5 m from an infinitely long line charge having linear charge density (λ) is 3-6 × 103 Vm-1. Find the value of λ.
Draw the pattern of electric field lines, when a point charge –Q is kept near an uncharged conducting plate.
Answer the following question.
Draw the pattern of electric field lines when a point charge +q is kept near an uncharged conducting plate.
Answer the following question.
Derive an expression for the electric field due to a dipole of dipole moment `vec"p"` at a point on its perpendicular bisector.
Explain why two field lines never cross each other at any point?
Which of the following figures represent the electric field lines due to a single negative charge?
The magnitude of the electric field due to a point charge object at a distance of 4.0 m is 9 N/C. From the same charged object the electric field of magnitude, 16 N/C will be at a distance of ______.
