Advertisements
Advertisements
प्रश्न
Two bar magnets are quickly moved towards a metallic loop connected across a capacitor ‘C’ as shown in the figure. Predict the polarity of the capacitor.

Advertisements
उत्तर

Left plate – Positive (+)
Right plate – Negative (−)
By Lenz’s law, the induced current opposes the approaching north poles, making both sides of the loop north and setting this polarity across the capacitor.
APPEARS IN
संबंधित प्रश्न
Why do the electrostatic field lines not form closed loops?
Which among the curves shown in the fig. cannot possibly represent electrostatic field lines?
(a)

(b)

(c)

(d)

(e)

(a) Derive an expression for the electric field E due to a dipole of length '2a' at a point distant r from the centre of the dipole on the axial line.
(b) Draw a graph of E versus r for r >> a.
(c) If this dipole were kept in a uniform external electric field E0, diagrammatically represent the position of the dipole in stable and unstable equilibrium and write the expressions for the torque acting on the dipole in both the cases.
A point charge (+Q) is kept in the vicinity of an uncharged conducting plate. Sketch the electric field lines between the charge and the plate?
The figure shows the field lines on a positive charge. Is the work done by the field in moving a small positive charge from Q to P positive or negative? Give reason.

Draw the pattern of electric field lines, when a point charge –Q is kept near an uncharged conducting plate.
Explain why two field lines never cross each other at any point?
A point positive charge is brought near an isolated conducting sphere (figure). The electric field is best given by ______.
Which of the following figures represent the electric field lines due to a single negative charge?
If Ea be the electric field strength of a short dipole at a point on its axial line and Ee that on the equatorial line at the same distance, then:
