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प्रश्न
The beaker is divided into two chambers A and B. The big circle represents solute and the small circles solvent.
(i) What can you say about the size of the holes in the membrane, if it is to behave semi- permeably between these two?
(ii) Will the solvent molecules pass through the membrane from left to right, from right to left, in either direction or in both directions?
(iii) In which direction will there be a net movement of solvent molecules?
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उत्तर
(i) The size of the holes in the membrane is large enough to allow only the solvent particles to pass through it. But solute particle cannot pass through it. Thus, the membrane acts as the semi-permeable.
(ii) Solvent molecules will pass through the membrane in both directions. Since solvent molecules are present on both the sides they will strike the semi-permeable membrane and pass through the same.
(iii) There is a net movement of solvent molecules from the place of its higher chemical potential to the place of its lower chemical potential, i.e., from right to left.
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संबंधित प्रश्न
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Movement of molecules of a substance from their higher concentration to lower concentration when they are in direct contact.
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Filtration and diffusion
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Comment on the nature (tonicity) of the liquid surrounding the cell.
Name the following:
The process by which raisins swell up when placed in a beaker of water.
Explain the term:
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The given statement is incorrect. Rewrite the correct statement:
Fresh water fish when placed in hypertonic salt solution absorb water and burst.
