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प्रश्न
Taking the volume of hydrogen as calculated in Q.19, what change must be made in Kelvin (absolute) temperature to return the volume to 2500 cm3 (pressure remaining constant)?
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उत्तर
V1 = 714.29 cm3
P1 = P2 = P
T1 = 273 K
V2 = 2500 cm3
T2= ?
By using Charles's Law,
`("P"_1 "V"_1)/"T"_1 = ("PV"_2)/"T"_2`
Since P is constant, it cancels out.
`"V"_1/"T"_1 = "V"_2/"T"_2`
T2 = `("V"_2 xx "T"_1)/"V"_1`
T2 = `(2500 xx 273)/714.29`
T2 = 3.5 × 273
T2 = 955.5 K
∴ T2 = 3.5 times
∴ The temperature must be increased 3.5 times.
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